如何在矩阵中扫描并对行和列求和

Question

include <stdio.h>

int main(){
    int number [5][5] , row=0, col=0,sumrow[5], sumcol[5];

        for(row=0;row<5;row++)
        {
            printf("Enter row %d ", row+1);

            for(col=0;col<5;col++)
            scanf("%d",&number[row][col]);
        }

// I want to read in row and col of numbers

       for(row=0;row<5,sumrow[row]=sumcol[col]=0;row++);
        for(row=0;row<5;row++)
            for(col=0;col<5;col++)
            {
                    sumrow[row]=sumrow[row]+number[row][col];
                    sumcol[col]=sumrow[col]+number[row][col];
            }
        // here I want to plus all the row in sumrow and col in sumcol

     printf("Row totals ");
        for(row=0;row<5;row++) {
            printf("%d ",sumrow[row]);
        }
            printf("\n Row totals ");
            for(col=0;col<5;col++){
            printf("%d ",sumrow[col]);
            }

    return 0;
    }

此代码无效。我想读取矩阵以及所有行和列。不知道是什么问题

Answer 1

我不知道我是否理解正确，但是如果你想对矩阵的所有元素求和你应该使用这个例如：

int a[5][5],n,m,i,j, soma=0;
printf("Enter value of m and n: ");
scanf("%d%d",&m,&n);
printf("\nEnter elemets of the matrix:\n");

for(i=0;i<m;++i)
for(j=0;j<n;++j)
    scanf("%d",&a[i][j]);

for(i=0;i<m;++i){
    sum_col += i;
}

for(j=0;j<n;++j){
    sum_row += ;
}

printf("\nYour sum is: %d", soma);
getch();
return 0;

PS：我也用了conio库，所以一开始应该用#include<conio.h>

但是如果你想将行数和列数求和并逐一打印，你应该使用这个：

int number [5][5] , row=0, col=0,sumrow=0, sumcol=0, cont_1=0, cont_2=0;


        for(row=0;row<5;row++)
        {
            printf("Enter row %d ", row+1);

            for(col=0;col<5;col++)
            scanf("%d",&number[row][col]);
        }

// I want to read in row and col of numbers

       for(row=0;row<5;row++){
            cont_1++;
            for(col=0;col<5;col++)
            {
                    sumcol += number[row][col];

            }
            printf("\nThe sum of Col %d is %d", cont_1, sumcol);
            sumcol = 0;
       }

       for(col=0;col<5;col++){
            cont_2++;
            for(row=0;row<5;row++) 
            {
                    sumrow += number[row][col];

            }
            printf("\nThe sum of Row %d is %d", cont_2, sumrow);
            sumrow = 0;
       }


    return 0;

我只是让你的代码更清晰，所以你应该明白你在做什么。

Answer 2

如果你想添加行和列的所有元素或者所有行和列的总和下面是代码，

#include <stdio.h>

int main ()
{
    static int array[10][10];
    int i, j, m, n, sum = 0;
    int rowSum = 0;
    int colSum = 0;
    printf("Enter the order of the matrix\n");
    scanf("%d %d", &m, &n);
    printf("Enter the elements of the matrix\n");
    for (i = 0; i < m; ++i)
    {
        for (j = 0; j < n; ++j)
        {
           scanf("%d", &array[i][j]);
        }
    }
    for (i = 0; i < m; ++i)
    {
        for (j = 0; j < n; ++j)
        {
           sum = sum + array[i][j] ;
        }
        printf("Sum of the %d row is = %d\n", i, sum);
    rowSum += sum;
    sum = 0;
    }
    printf("Sum of all the row is = %d\n", rowSum);
    sum = 0;
    for (j = 0; j < n; ++j)
    {
       for (i = 0; i < m; ++i)
       {
         sum = sum + array[i][j];
       }
       printf("Sum of the %d column is = %d\n", j, sum);
       colSum += sum;
       sum = 0;
    }
    printf("Sum of all the column is = %d\n", colSum);
 }

如何在矩阵中扫描并对行和列求和

How to scan in matrix and add sum the row and col

c

row

sum

matrix