如何编写与使用它的 class 具有相同导入的装饰器？

Question

如何在 Python 中编写装饰器，它有一些导入 from Foo import Foo，当我想将它用于 class 的方法时，它也是必需的有这个导入吗？

将导入放入两个单独的文件会导致错误，告诉我无法从 Foo 导入 Foo。

如果不可能，那么这个：如果装饰器不会在其他任何地方使用，将装饰器放入与 class 相同的文件中，这样我只需要编写一次导入，就不会发生冲突，这是个好主意吗？与任何其他导入？

在我的真实示例中，我想写一个装饰器，它只是更改一个标志，该标志指示列表是否已更改。 class 中修改列表的每个方法都将使用该装饰器进行装饰。

编辑#1：

更改代码结构后，我现在只有两个参与的源代码文件。这些是：

# -*- coding: utf-8 -*-
from AppSettings import AppSettings
from FileManager import FileManager
from decorators.changesvocables import changesvocables
from exceptions.DuplicateVocableException import DuplicateVocableException
from exceptions.UnknownVocableException import UnknownVocableException

__author__ = 'xiaolong'


class VocableManager:

    vocables = []
    search_result = []
    vocables_changed = False

    test_counter = 0
    test_call_counter = 0

    def __init__(self):
        pass

    @classmethod
    @changesvocables
    def remove_vocable(cls, vocable):
        VocableManager.test_call_counter += 1
        if vocable in VocableManager.vocables:
            VocableManager.test_counter += 1
            VocableManager.vocables.remove(vocable)
            # del vocable
        else:
            print(vocable)
            raise UnknownVocableException('Vocable not found.')
        # VocableManager.vocables_changed = True

    @classmethod
    @changesvocables
    def remove_vocable_by_index(cls, index):
        del VocableManager.vocables[index]
        # VocableManager.vocables_changed = True

    @classmethod
    @changesvocables
    def add_vocable(cls, vocable):
        if vocable not in VocableManager.vocables:
            VocableManager.vocables.append(vocable)
        else:
            raise DuplicateVocableException('The vocable already exists.')
        # VocableManager.vocables_changed = True

在那之后class仍然继续，但没有其他方法带有changesvocables修饰。如果需要，我可以添加整个 class.

装饰器：

# -*- coding: utf-8 -*-
from functools import wraps
from VocableManager import VocableManager as VocMan

__author__ = 'xiaolong'


def changesvocables(function):
    @wraps(function)
    def wrapper(*args, **kw):
        result = function(*args, **kw)
        VocMan.vocables_changed = True
        return result
    return wrapper

当我尝试运行应用程序时，这会导致以下错误：

** (__main__.py:16991): WARNING **: Couldn't connect to accessibility bus: Failed to connect to socket /tmp/dbus-sQwlsgyRi2: Connection refused
Traceback (most recent call last):
  File "/home/xiaolong/development/pycharm-workspace/gtkplus-tool/gtkplustool/__main__.py", line 1, in <module>
    from Application import Application
  File "/home/xiaolong/development/pycharm-workspace/gtkplus-tool/gtkplustool/Application.py", line 8, in <module>
    from VocableManager import VocableManager
  File "/home/xiaolong/development/pycharm-workspace/gtkplus-tool/gtkplustool/VocableManager.py", line 4, in <module>
    from decorators.changesvocables import changesvocables
  File "/home/xiaolong/development/pycharm-workspace/gtkplus-tool/gtkplustool/decorators/changesvocables.py", line 3, in <module>
    from VocableManager import VocableManager as VocMan
ImportError: cannot import name 'VocableManager'

编辑#3：

这是一个 MCVE：

main.py:

# -*- coding: utf-8 -*-
from mcve.ListManager import ListManager

__author__ = 'xiaolong'

if __name__ == '__main__':
    list_manager = ListManager()
    list_manager.add_item('item1')

装饰师：

# -*- coding: utf-8 -*-
from functools import wraps
from mcve.ListManager import ListManager as ListMan

__author__ = 'xiaolong'


def changesitems(function):
    @wraps(function)
    def wrapper(*args, **kw):
        result = function(*args, **kw)
        ListMan.vocables_changed = True
        return result
    return wrapper

列表管理器：

# -*- coding: utf-8 -*-
from mcve.changesitems import changesitems


class ListManager:

    list_of_items = []

    def __init__(self):
        pass

    @changesitems
    def add_item(self, item):
        if item not in ListManager.list_of_items:
            ListManager.add_item(item)

与之前相同的错误：

Traceback (most recent call last):
  File "/home/xiaolong/development/pycharm-workspace/MCVE/mcve/main.py", line 2, in <module>
    from mcve.ListManager import ListManager
  File "/home/xiaolong/development/pycharm-workspace/MCVE/mcve/ListManager.py", line 2, in <module>
    from mcve.changesitems import changesitems
  File "/home/xiaolong/development/pycharm-workspace/MCVE/mcve/changesitems.py", line 3, in <module>
    from mcve.ListManager import ListManager as ListMan
ImportError: cannot import name 'ListManager'

Process finished with exit code 1

Answer 1

尝试：

from Foo import Foo as foo

现在您可以访问包，Foo，以及装饰器，foo。

如何编写与使用它的 class 具有相同导入的装饰器？

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