AngularJS 承诺数组
AngularJS Array of Promises
任何人都可以帮我一些 Angular promises 吗?我有以下函数,它们应该接收一组文件对象,遍历它们,然后上传每个文件对象。在每次迭代期间,一个 promise 对象被推送到 promises
的数组中。在我的 upload
函数中,我有一个附加了 .then()
的 cycle
函数,在所有 promise 对象都已解析之前不应调用该函数。我认为我的代码看起来是正确的,但它不能正常工作。图片上传,但立即调用 cycle(files).then()
,而不是在 promises
数组解析后调用。
function upload(files) {
var uploadCount = files.length;
function cycle(files) {
var promises = [];
for (var i = 0; i < files.length; i++) {
var deferred = $q.defer();
promises.push(deferred);
var file = files[i];
Upload.upload({
url: '/photos.json',
file: file
}).success(function(){
$scope.progressCurrentCount += 1;
deferred.resolve();
});
};
return $q.all(promises);
};
cycle(files).then(function(result) {
if(uploadCount > 1) {
$scope.lastAction = 'uploaded ' + uploadCount + ' photos';
} else {
$scope.lastAction = 'uploaded ' + uploadCount + ' photo';
}
$scope.showSuccessModal = true;
$scope.uploading = false;
$scope.failedUploads = [];
$scope.newPhotos = {
token: $scope.token,
files: undefined
};
photoUploadBtn.removeClass('disabled');
})
};
最终工作代码*
而不是设置 var deferred = $q.defer();
将 deferred.promise
推入 promises
数组,然后在我的 .success()
回调中解析 deferred
,这是行不通的,我只是将没有 .success()
回调的 Upload.upload()
函数推送到 promises
,然后将其传递给 $q.all()
,它完成所有提升。
function upload(files) {
var uploadCount = files.length;
function cycle(files) {
var promises = [];
for (var i = 0; i < files.length; i++) {
var file = files[i];
var promise = Upload.upload({
url: '/photos.json',
file: file
});
promises.push(promise);
};
return $q.all(promises);
};
cycle(files).then(function(result) {
if(uploadCount > 1) {
$scope.lastAction = 'uploaded ' + uploadCount + ' photos';
} else {
$scope.lastAction = 'uploaded ' + uploadCount + ' photo';
};
$scope.showSuccessModal = true;
$scope.uploading = false;
$scope.failedUploads = [];
$scope.newPhotos = {
token: $scope.token,
files: undefined
};
photoUploadBtn.removeClass('disabled');
getPhotos(q);
})
};
您必须将承诺而非延迟推送到 promises
数组:
promises.push(deferred.promise);
如果你这样想会有所帮助:
- promise 是您想要 return 给消费者的只读对象
- deferred 是该只读承诺的修饰符,您想自己保留它
任何人都可以帮我一些 Angular promises 吗?我有以下函数,它们应该接收一组文件对象,遍历它们,然后上传每个文件对象。在每次迭代期间,一个 promise 对象被推送到 promises
的数组中。在我的 upload
函数中,我有一个附加了 .then()
的 cycle
函数,在所有 promise 对象都已解析之前不应调用该函数。我认为我的代码看起来是正确的,但它不能正常工作。图片上传,但立即调用 cycle(files).then()
,而不是在 promises
数组解析后调用。
function upload(files) {
var uploadCount = files.length;
function cycle(files) {
var promises = [];
for (var i = 0; i < files.length; i++) {
var deferred = $q.defer();
promises.push(deferred);
var file = files[i];
Upload.upload({
url: '/photos.json',
file: file
}).success(function(){
$scope.progressCurrentCount += 1;
deferred.resolve();
});
};
return $q.all(promises);
};
cycle(files).then(function(result) {
if(uploadCount > 1) {
$scope.lastAction = 'uploaded ' + uploadCount + ' photos';
} else {
$scope.lastAction = 'uploaded ' + uploadCount + ' photo';
}
$scope.showSuccessModal = true;
$scope.uploading = false;
$scope.failedUploads = [];
$scope.newPhotos = {
token: $scope.token,
files: undefined
};
photoUploadBtn.removeClass('disabled');
})
};
最终工作代码*
而不是设置 var deferred = $q.defer();
将 deferred.promise
推入 promises
数组,然后在我的 .success()
回调中解析 deferred
,这是行不通的,我只是将没有 .success()
回调的 Upload.upload()
函数推送到 promises
,然后将其传递给 $q.all()
,它完成所有提升。
function upload(files) {
var uploadCount = files.length;
function cycle(files) {
var promises = [];
for (var i = 0; i < files.length; i++) {
var file = files[i];
var promise = Upload.upload({
url: '/photos.json',
file: file
});
promises.push(promise);
};
return $q.all(promises);
};
cycle(files).then(function(result) {
if(uploadCount > 1) {
$scope.lastAction = 'uploaded ' + uploadCount + ' photos';
} else {
$scope.lastAction = 'uploaded ' + uploadCount + ' photo';
};
$scope.showSuccessModal = true;
$scope.uploading = false;
$scope.failedUploads = [];
$scope.newPhotos = {
token: $scope.token,
files: undefined
};
photoUploadBtn.removeClass('disabled');
getPhotos(q);
})
};
您必须将承诺而非延迟推送到 promises
数组:
promises.push(deferred.promise);
如果你这样想会有所帮助:
- promise 是您想要 return 给消费者的只读对象
- deferred 是该只读承诺的修饰符,您想自己保留它