PHP 正则表达式查找单词（即使是双字母）然后替换它

Question

我正在使用 PHP 创建字符串过滤器。我需要用其他词替换一些词，所以我正在使用 str_replace() 函数，如下所示：

$phrase  = "You should eat fruits, vegetables, and fiber every day.";
$healthy = array("fruits", "vegetables", "fiber");
$yummy   = array("pizza", "beer", "ice cream");
$newphrase = str_replace($healthy, $yummy, $phrase);
// echo -> "You should eat pizza, beer, and ice cream every day.";

到目前为止一切顺利，但我需要替换单词，即使它们包含多个这样的字母：

$phrase  = "You should eat fruuits, vegetaaables, and fiiibeeer every day.";

我发现这个示例删除字符串中的双字母：

$string = preg_replace('/(\w)+/', '', $phrase);

但是如果我将这个例子应用到我的字符串中，所有带有双字母的单词都会被改变...例如 "Google" 将变成 "Gogle" 而我不希望那样。

有什么想法吗？谢谢！

Answer 1

如果您想要特定的词，那么您可以在 preg_replace 中使用多个模式。

对于您的示例，您可以使用多种模式，如下所示：

$phrase  = "You should eat fruits, vegetables, and fiber every day.";
$patterns = array("/fru+its/", "/vegeta+bles/", "/fi+be+r/");
$yummy   = array("pizza", "beer", "ice cream");
$newphrase = preg_replace($patterns, $yummy, $phrase);

如果您只想检测 fruits、vegetables 和 fiber，那么您可以使用：

$patterns = array("f+r+u+i+t+s+", "v+e+g+e+t+a+b+l+e+s+", "f+i+b+e+r+");

Regex demo

IdeOne code example

Answer 2

我会做这样的事情

$phrase  = "You should eat suck, sck, and suuucky every day.";
$healthy = 's+u*c+k+';
$yummy = 'luck';
$newphrase = preg_replace('/' . $healthy . '/', $yummy, $phrase);
echo $newphrase;

输出：

You should eat luck, luck, and lucky every day.

+ 是量词，表示前面一个或多个字符。 * 是一个零个或多个量词，这意味着该字符不必存在，但如果它是任意数量的字符，则可以存在。

演示：https://regex101.com/r/sN5sZ6/1

还应使用 ass 字边界，因为您不想替换 class 等。https://regex101.com/r/oM4wY1/2 有点变成一条蜿蜒的道路..

Answer 3

工作示例

$word =array('fiber', 'milk', 'nuts'); // words to scan for
$phrase = "You should eat fibeeer, nuuuuts, and milkkk every day."; //phrase
$filter = array(); // array of dynamicly generated filters

foreach($word as $name){ // loop for filter generating
    $temp = str_split($name);
    $temp = implode('{1,}', $temp). '{1,}';
    $filter[$name] = $temp;
}


$phraseTable = explode(' ', $phrase); // getting phrase into an array

foreach($phraseTable as &$data){ // scanning phrase
    foreach($filter as $name => $value){
         if(  preg_match( '/'.$value.'[,.]?/', $data)){
             $data = $name;
    }  
    } 
}       

$phraseScanned = implode(' ', $phraseTable); // imploding formatted phrase
echo $phraseScanned;  // echo result

PHP 正则表达式查找单词（即使是双字母）然后替换它

PHP regex find word (even with double letters) then replace it

php

regex

string

preg-replace

str-replace