如何从 Flask 中的 QuerySelectField 传递数据？

Question

在我的应用程序中，我有一个 QuerySelectField 来填充下拉菜单。我从数据库中获取查询 select 字段的选择详细信息。一旦用户 select 从下拉菜单中选择任何选项并单击 POST 方法的提交按钮，我想将用户 select 从下拉菜单编辑的值传递给数据库进行存储。但它总是 return 来自查询 select 字段的值 None。所以 db 将数据存储为 None.

models.py

class Orders(db.Model):
    __tablename__ = 'orders'
    id = db.Column(db.Integer, primary_key=True)
    name = db.Column(db.String(64))
    email = db.Column(db.String(120))
    resturant = db.Column(db.String(64))
    food = db.Column(db.String(64)))

forms.py

def possible_res():
    return Resturant.query.all()

def possible_menu():
    return Menu.query.all()

class OrderForm(Form):

    sel_res = QuerySelectField(query_factory=possible_res,
                               get_label='name')

    sel_menu = QuerySelectField(query_factory=possible_menu,
                                get_label='food',
                                allow_blank=False
                                )
    submit = SubmitField("Confirm")

views.py

@app.route('/resturant', methods=['GET','POST'])
def resturant():
    form = OrderForm()
    if request.method == 'GET':
        test = form.sel_menu.data
        return render_template("make_order.html", form=form, test=test)
    else:
        a = User.query.filter_by(email = session['email']).all()
        for u in a:
            name = u.firstname

        b = Orders(name=name, email=session['email'])
        b.resturant = form.sel_res.data
        b.food = form.sel_menu.data
        db.session.add(b)
        db.session.commit()
        return redirect('/')

Answer 1

QuerySelectField#__init__'s query_factory argument should return a SQLAlchemy Query object, not a Python list. WTForms will materialize the query itself, by iterating over it。只需将您的工厂函数更改为 return query 属性，而不是列表：

def possible_res():
    return Resturant.query

def possible_menu():
    return Menu.query

如何从 Flask 中的 QuerySelectField 传递数据？

How to pass data from a QuerySelectField in flask?

python

flask

flask-wtforms