每当我在 IDLE 环境中启动程序时，如何修复 Python 重新启动？

Question

import random

winning_conditon = 0
no_of_guesses = 0
comp_guess = random.randint(1,100)

while (no_of_guesses == 11) or (winning_conditon == 1):
    user_guess = int(input("What is your guess? "))
    if user_guess < 1 or user_guess > 100:
        print("Your number is invalid!")

    elif comp_guess == user_guess:
        print("Well Done!")
        winning_condition = 1
    elif comp_guess < user_guess:
        print("Your number is too high!")
    elif comp_guess > user_guess:
        print("Your number is too low!")

    no_of_guesses = no_of_guesses + 1
    print(no_of_guesses)
print("You haven't guessed the right amount of times or u won.")

每当我启动 python IDLE（我使用的是 Portable Python 3.2.5.1 (http://portablepython.com/wiki/PortablePython3.2.5.1/)）时，它会出现一条重启消息，然后显示一个“=”签署并且不继续该程序。你知道解决办法吗？

Answer 1

当我运行你的程序时，我得到这个输出：

Python 3.2.5 (default, May 15 2013, 23:06:03) [MSC v.1500 32 bit (Intel)] on win32
Type "copyright", "credits" or "license()" for more information.
>>> ================================ RESTART ================================
>>> 
You haven't guessed the right amount of times or u won.
>>>

这很好，符合预期。

我会这样修改你的程序：

while not (no_of_guesses == 11 or winning_conditon == 1)

while not 相当于 until.

每当我在 IDLE 环境中启动程序时，如何修复 Python 重新启动？

How to fix Python restarting whenever I start program on IDLE environment?

python

shell

python-idle