lua尝试调用对象方法并出现 lua 错误时绑定中止

Question

我使用 http://www.rasterbar.com/products/luabind/docs.html#deriving-in-lua 中的示例在 c++ 中定义了一个 class，我可以从 lua:

中派生

class base
{
public:
    base(const char* s)
    { std::cout << s << "\n"; }

    virtual void f(int a)
    { std::cout << "f(" << a << ")\n"; }
};

struct base_wrapper : base, luabind::wrap_base
{
    base_wrapper(const char* s)
        : base(s)
    {}

    virtual void f(int a)
    {
        call<void>("f", a);
    }

    static void default_f(base* ptr, int a)
    {
        return ptr->base::f(a);
    }
};

...

module(L)
[
    class_<base, base_wrapper>("base")
        .def(constructor<const char*>())
        .def("f", &base::f, &base_wrapper::default_f)
];

然后我在 lua 中创建了一个派生的 class:

class 'base_derived' (base)

function base_derived:__init(str)
    base.__init(self,str)
end

function base_derived:f()
    this_function_doesnt_exist()
end

任何对 'f' 的调用都应该抛出 lua 错误，如果我在 lua:

中这样做，它会正常工作

local x = base_derived("Test")
x:f() -- Throws "attempt to call a nil value..." error

我想做同样的事情，但在 C++ 中：

auto g = luabind::globals(l);
auto r = g["base_derived"];
if(r)
{
    luabind::object o = r("Test");
    auto gm = luabind::object_cast<base_wrapper*>(o);
    if(gm != nullptr)
    {
        try
        {
            luabind::call_member<void>(o,"f",5);
        }
        catch(luabind::error &e)
        {
            std::cout<<"[LUA] Error: "<<e.what()<<std::endl;
        }
    }
    o.push(l);
}

但是 'luabind::call_member'-调用导致 'luabind/detail/call_member.hpp' 中止，第 258 行：

// Code snippet of luabind/detail/call_member.hpp
~proxy_member_void_caller()
{
    if (m_called) return;

    m_called = true;

    // don't count the function and self-reference
    // since those will be popped by pcall
    int top = lua_gettop(L) - 2;

    // pcall will pop the function and self reference
    // and all the parameters

    push_args_from_tuple<1>::apply(L, m_args);
    if (pcall(L, boost::tuples::length<Tuple>::value + 1, 0))
    {
        assert(lua_gettop(L) == top + 1);
#ifndef LUABIND_NO_EXCEPTIONS
////////////////////////////////////////////
        throw luabind::error(L); // LINE 258
////////////////////////////////////////////
#else
        error_callback_fun e = get_error_callback();
        if (e) e(L);

        assert(0 && "the lua function threw an error and exceptions are disabled."
            "If you want to handle this error use luabind::set_error_callback()");
        std::terminate();
#endif
    }
    // pops the return values from the function
    stack_pop pop(L, lua_gettop(L) - top);
}

该行中的异常实际上并未抛出，但它是导致中止的原因。

但是，仅当 lua 函数导致 lua 错误时才会发生中止。如果我评论 'this_function_doesnt_exist()'-调用，lua- 和 c++-版本运行都很好。

为什么 'throw luabind::error(L);' 会导致中止？即使存在潜在的 lua 错误，我该怎么做才能安全地从 C++ 调用该函数？

// 编辑：这是中止时的调用堆栈（调用'luabind::call_member(o,"f",5);'时）：

>   vcruntime140d.dll!__CxxFrameHandler(EHExceptionRecord * pExcept, unsigned __int64 RN, _CONTEXT * pContext, _xDISPATCHER_CONTEXT * pDC) Line 213 C++
    ntdll.dll!RtlpExecuteHandlerForException()  Unknown
    ntdll.dll!RtlDispatchException()    Unknown
    ntdll.dll!KiUserExceptionDispatch() Unknown
    KernelBase.dll!RaiseException() Unknown
    vcruntime140d.dll!_CxxThrowException(void * pExceptionObject, const _s__ThrowInfo * pThrowInfo) Line 136    C++
    server.dll!luabind::detail::proxy_member_void_caller<boost::tuples::tuple<int const * __ptr64,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type> >::~proxy_member_void_caller<boost::tuples::tuple<int const * __ptr64,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type,boost::tuples::null_type> >() Line 258    C++

这是中止消息：

Answer 1

参见第 254 行：

if (pcall(L, boost::tuples::length<Tuple>::value + 1, 0))

在这里，pcall 要求 lua 执行您的 x:f(5) 等效调用。显然这段代码 returns 是一个错误，因为 pcall() returns 不同于零。这是预料之中的，因为您确实通过调用 this_function_doesnt_exist() 在 lua 中创建了一个错误。这也解释了为什么在您评论 this_function_doesnt_exist() 调用时不会发生中止。

然后，到C++代码：

     throw luabind::error(L);

这个错误是从析构函数中抛出的：~proxy_member_void_caller()，结果是throwing an exception from a destructor is bad practice. This problem is known for luabind (see this question)甚至没有抛出就触发了abort的调用。

解决方法是在~proxy_member_void_caller()的签名中加上noexcept(false)，像这样：

~proxy_member_void_caller() noexcept(false)

lua尝试调用对象方法并出现 lua 错误时绑定中止

luabind abort when trying to call object method with lua errors

c++

lua

exception

abort

luabind