坚持我制作的这段代码

Question

如果您从我创建的列表中输入一个通用密码，此代码应该显示 "please enter a new password"，但它不会，它只是显示 "Password Accepted"，但不应该。谁能帮帮我吗？这是代码本身：

### Asks user for their name and password ###

print "Hello, what is your name?"

### Stores name in variable myName ###

myName = raw_input()

print "Nice to meet you "+myName+", please enter a password to continue."

common_passwords = [ '123456', 'password', '12345', '12345678', 'qwerty',
                     '1234567890', 'baseball', 'dragon', 'football', '1234567',
                     'monkey', 'letmein', 'abc123', '111111', 'mustang', 'access',
                     'shadow', 'master', 'michael', 'superman', '696969', '123123',
                     'batman', 'trustno1']

while True:
    password = raw_input()
    if len(password) < 8:
        print "Password is less than 8 characters."
        print "Your password has to be 8 characters or more."
        continue
    found = False
    for cpass in common_passwords:
        if cpass == password:
            print "You have selected a common password"
            print "Please choose a new password"
            found = True
            break
        if not found:
            print "Password Accepted"
            break

Answer 1

你想做的可能是：

for cpass in common_passwords:
        if cpass == password:
            print "You have selected a common password"
            print "Please choose a new password"
            found = True
            break  
if not found:
        print "Password Accepted"

因为你要检查输入的密码是否在common_password中，如果不是在你的循环之后，密码就可以了。

此外，您可以简单地检查密码是否存在：

If password in common_passwords:
        print "You have selected a common password"
        print "Please choose a new password"
else :
        print "Password Accepted"

Answer 2

尝试if password in common_passwords，它将一次测试所有常用密码。您当前的错误是，当您遍历每个元素时，如果 commom_passwords 中的元素如果第一个不匹配，它将接受它。

坚持我制作的这段代码

Stuck with this code I have made

python

passwords

python-2.7