symfony if 库中的函数

Question

我正在尝试在存储库中执行此功能

public function getInfoAsManagers()
{
    $q = $this->createQueryBuilder('user');
    $q->select(['user.id', 'user.firstName', 'user.lastName', 'position.name', 'IF(COUNT(mpkManager.user)>0, 1, 0) as isManager']);
    $q->leftJoin('user.position', 'position', 'WITH', 'user.position=position');
    $q->leftJoin('PCK\ExtraBundle\Entity\MpkManager', 'mpkManager', 'WITH', 'mpkManager.user=user');
    $q->groupBy('user');

    return $q->getQuery()->getResult();
}

但我已经在屏幕上了

[Syntax Error] line 0, col 62: Error: Expected known function, got 'IF'

如何在自定义查询中使用 IF 函数？

我可以使用这样的东西吗？

$q->addSelect(DB::raw('PURE SQL'));

Answer 1

只需添加 createNativeQuery()

或案例

$em = $this->getDoctrine()->getEntityManager();
$qb = $em->createQueryBuilder();
$q = $qb
  ->select("c.id")
  ->addSelect("CASE WHEN (c.parent IS NULL) THEN c.name ELSE 'something' END")
  ->from("MyBundle:Category", "c")
  ->leftJoin("c.parent", "t");

echo $q->getQuery()->getSQL();

否则添加函数

http://docs.doctrine-project.org/projects/doctrine-orm/en/latest/reference/dql-doctrine-query-language.html#adding-your-own-functions-to-the-dql-language

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