Jpa 多对多关系，生成错误 sql 查询

Question

我有一个房客对象，有可能有很多联系。同一个联系人可以关联到多个房客。这是多对多的关系。

在我的房客中，

@ManyToMany(mappedBy = "lodger")
private List<Contact> contactList;

在联系中，我有

@ManyToMany
@JoinTable(name = "lodger_contact", joinColumns = @JoinColumn(name = "lodger_id"), inverseJoinColumns = @JoinColumn(name = "contact_id"))
private List<Lodger> lodger;

我用的是spring-jpa数据。使用的 Jpa 实现是 hibernate

在我的联系人存储库界面中，我创建了这个方法

List<Contact> findByLodgerLodgerIdNot(Long lodgerId);

我有一个房客和一个联系人（他们没有关联）。当我调用此方法时，不会返回任何内容。

生成的查询是

    select
    contact0_.contact_id as contact_1_9_,
    contact0_.address as address2_9_,
    contact0_.city_cityId as city_cit5_9_,
    contact0_.contact_sub_category_contactSubCategoryId as contact_6_9_,
    contact0_.first_name as first_na3_9_,
    contact0_.last_name as last_nam4_9_,
    contact0_.phone_phoneId as phone_ph7_9_ 
from
    contact contact0_ 
left outer join
    lodger_contact lodger1_ 
        on contact0_.contact_id=lodger1_.lodger_id 
left outer join
    lodger lodger2_ 
        on lodger1_.contact_id=lodger2_.lodger_id 
where
    lodger2_.lodger_id<>?

编辑，我完成了 JB Nizet 要求的更改

select
    contact0_.contact_id as contact_1_9_,
    contact0_.address as address2_9_,
    contact0_.city_cityId as city_cit5_9_,
    contact0_.contact_sub_category_contactSubCategoryId as contact_6_9_,
    contact0_.first_name as first_na3_9_,
    contact0_.last_name as last_nam4_9_,
    contact0_.phone_phoneId as phone_ph7_9_ 
from
    contact contact0_ 
left outer join
    lodger_contact lodger1_ 
        on contact0_.contact_id=lodger1_.contact_id 
left outer join
    lodger lodger2_ 
        on lodger1_.lodger_id=lodger2_.lodger_id 
where
    lodger2_.lodger_id<>?

同样的结果

编辑 2

有了这个代码，就可以了

@Query("select c from Contact c where :lodger not member of c.lodger")
List<Contact> findByLodgerLodgerIdNot(@Param("lodger") Lodger lodger);

是否可以使用 lodgerId 而不是使用 lodger？

即生成此代码

select
    contact0_.contact_id as contact_1_9_,
    contact0_.address as address2_9_,
    contact0_.city_cityId as city_cit5_9_,
    contact0_.contact_sub_category_contactSubCategoryId as contact_6_9_,
    contact0_.first_name as first_na3_9_,
    contact0_.last_name as last_nam4_9_,
    contact0_.phone_phoneId as phone_ph7_9_ 
from
    contact contact0_ 
where
    ? not in  (
        select
            lodger1_.lodger_id 
        from
            lodger_contact lodger1_ 
        where
            contact0_.contact_id=lodger1_.contact_id

编辑 3

@Query("select c from Contact c where :lodgerId not member of c.lodger.lodgerId")
List<Contact> findByLodgerLodgerIdNot(@Param("lodgerId") Long lodger);

org.hibernate.QueryException: illegal attempt to dereference collection [contact0_.contact_id.lodger] with element property reference [lodgerId]

Answer 1

正如您从生成的 JPQL 中看到的那样，您的映射是错误的：Hibernate 在 contact_id = lodger_id 上连接表（反之亦然），而不是在 contact_id = contact_id 上连接它们（并且 lodger_id = lodger_id).

那是因为你用 inverseJoinColumns 反转了 joinColumns。映射应该是

@JoinTable(name = "lodger_contact", 
           joinColumns = @JoinColumn(name = "contact_id"), 
           inverseJoinColumns = @JoinColumn(name = "lodger_id"))

Jpa 多对多关系，生成错误 sql 查询

Jpa many to many relation, bad sql query generated

hibernate

jpa

spring-data

spring-data-jpa