MySql 逻辑排序依据

Question

我目前有这样的查询：

SELECT 'id', 'clanid', 'name',
       'level', 'exp', 'warwinpercent',
       'warswon', 'warslost', 'warstied',
       'playercount', 'score'
FROM clans
WHERE warswon >= 100
ORDER BY warwinpercent DESC, warswon DESC;

现在可行，但最终它并不像我希望的那样合乎逻辑...

例如

假设有一行具有 99.5738% war 的获胜百分比和 208 war 次获胜。另一个有 100% war 的胜率和 103 war 的获胜率。

我希望 99% 的行位于 100% 的行之上。我有什么方法可以让它工作吗？

我的公式是：

warinpercent = warswon/(warswon+warstied+warlost)*100
order by warwinpercent
if warwinpercent are in a range of 3% then order by warswon between them.

Answer 1

我建议使用 How Not To Sort By Average Rating

中的顺序

PROBLEM:

You need some sort of "score" to sort by.

WRONG SOLUTION #1: Score = (Positive ratings) - (Negative ratings)

WRONG SOLUTION #2: Score = Average rating = (Positive ratings) / (Total ratings)

CORRECT SOLUTION: Score = Lower bound of Wilson score confidence interval for a Bernoulli parameter

演示：

CREATE TABLE clans(id INT, name VARCHAR(100), warswon INT, warslost INT);

INSERT INTO clans VALUES (1, 'aaa',  208, 6), (2, 'bbb', 103, 0);

SELECT id, name,warswon, warslost,((warswon + 1.9208) / (warswon + warslost) - 
                 1.96 * SQRT((warswon * warslost) / (warswon + warslost) + 0.9604) / 
                          (warswon + warslost)) / (1 + 3.8416 / (warswon + warslost)) 
       AS ci_lower_bound 
FROM clans 
ORDER BY ci_lower_bound DESC;

SqlFiddleDemo

输出：

╔═════╦═══════╦══════════╦═══════════╦════════════════════╗
║ id  ║ name  ║ warswon  ║ warslost  ║   ci_lower_bound   ║
╠═════╬═══════╬══════════╬═══════════╬════════════════════╣
║  2  ║ bbb   ║     103  ║        0  ║ 0.9640439675800224 ║
║  1  ║ aaa   ║     208  ║        6  ║ 0.9401908847803808 ║
╚═════╩═══════╩══════════╩═══════════╩════════════════════╝

MySql 逻辑排序依据

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