删除带有特殊字符“\”和“/”的单词

Question

在推文分析过程中，我运行在 "words" 中有 \ 或 /（可能在一个 "word" 中出现不止一次）。我想完全删除这些词，但不能完全确定

这是我试过的：

sen = 'this is \re\store and b\fre'
sen1 = 'this i\s /re/store and b//fre/'

slash_back =  r'(?:[\w_]+\[\w_]+)'
slash_fwd = r'(?:[\w_]+/+[\w_]+)'
slash_all = r'(?<!\S)[a-z-]+(?=[,.!?:;]?(?!\S))'

strt = re.sub(slash_back,"",sen)
strt1 = re.sub(slash_fwd,"",sen1)
strt2 = re.sub(slash_all,"",sen1)
print strt
print strt1
print strt2

我想得到：

this is and
this i\s and
this and

但是，我收到：

and 
this i\s / and /
i\s /re/store  b//fre/

补充：在这种情况下，"word" 是一个由空格或标点符号分隔的字符串（如常规文本）

Answer 1

这个怎么样？我添加了一些标点符号示例：

import re

sen = r'this is \re\store and b\fre'
sen1 = r'this i\s /re/store and b//fre/'
sen2 = r'this is \re\store, and b\fre!'
sen3 = r'this i\s /re/store, and b//fre/!'

slash_back =  r'\s*(?:[\w_]*\(?:[\w_]*\)*[\w_]*)'
slash_fwd = r'\s*(?:[\w_]*/(?:[\w_]*/)*[\w_]*)'
slash_all = r'\s*(?:[\w_]*[/\](?:[\w_]*[/\])*[\w_]*)'

strt = re.sub(slash_back,"",sen)
strt1 = re.sub(slash_fwd,"",sen1)
strt2 = re.sub(slash_all,"",sen1)
strt3 = re.sub(slash_back,"",sen2)
strt4 = re.sub(slash_fwd,"",sen3)
strt5 = re.sub(slash_all,"",sen3)
print(strt)
print(strt1)
print(strt2)
print(strt3)
print(strt4)
print(strt5)

输出：

this is and
this i\s and
this and
this is, and!
this i\s, and!
this, and!

Answer 2

没有 re 的一种方法是 join 和理解力。

sen = 'this is \re\store and b\fre'
sen1 = 'this i\s /re/store and b//fre/'

remove_back = lambda s: ' '.join(i for i in s.split() if '\' not in i)
remove_forward = lambda s: ' '.join(i for i in s.split() if '/' not in i)

>>> print(remove_back(sen))
this is and
>>> print(remove_forward(sen1))
this i\s and
>>> print(remove_back(remove_forward(sen1)))
this and

删除带有特殊字符“\”和“/”的单词

Removing words with special characters "\" and "/"

python

regex

special-characters