如何 select 与我的 table 不同的列？

Question

我有两个 table 一起工作。第一个 table #CustomerList 我用值手动初始化。然后我在第一个 table #CustomerList 的基础上创建第二个 table #CustomerListWithRank_Id。

第一个和第二个 table 之间的唯一区别是第二个 table #CustomerListWithRank_Id 有一列为每一行提供行号，我在 SQL 代码，当我循环遍历 table.

所以我遇到的问题是我只想用 [FileName] 列中的唯一值初始化 #CustomerListWithRank_Id，我该怎么做？

SELECT '3004' Customer_No,'831001' DDD_Reference_No,'varer831.csv' [FileName]
INTO #CustomerList -- DROP TABLE #CustomerList
UNION ALL SELECT '3002' Customer_No,'199001' DDD_Reference_No,'varer199.csv' [FileName]
UNION ALL SELECT '3003' Customer_No,'199002' DDD_Reference_No,'varer199.csv' [FileName]

-

SELECT *, ROW_NUMBER() OVER (ORDER BY Customer_No) AS 'Rank_Id'
INTO #CustomerListWithRank_Id --DROP TABLE #CUstomerListWithRank_ID
FROM #CustomerList

如果我在上面的查询中使用 GROUP BY [FileName]，我会得到这个错误：

Msg 8120, Level 16, State 1, Line 1
Column '#CustomerList.Customer_No' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.

Answer 1

这是你需要的吗？

select *, ROW_NUMBER() OVER (ORDER BY Customer_No) AS 'Rank_Id'
INTO #CustomerListWithRank_Id 
from
(
    SELECT max(Customer_No) Customer_No, max(DDD_Reference_No) DDD_Reference_No, FileName
    FROM #CustomerList
    group by FileName
) t

Answer 2

这是你需要的吗

SELECT * INTO #CustomerListWithRank_Id From
(SELECT *, ROW_NUMBER() OVER (PARTITION BY FileName Order by Customer_No)  AS RowNum FROM CustomerList)

如何 select 与我的 table 不同的列？

How to select distinct column from my table?

sql

sql-server

group-by

distinct