如何修复递归 CTE 查询中的 "near 'with': syntax error" (flask/sqlalchemy)
How to fix "near 'with': syntax error" in recursive CTE query (flask/sqlalchemy)
我正在尝试重现在 SqlAlchemy 文档页面上找到的 this 查询。在 models.py
中设置 Part
class 之后,这就是我所拥有的:
from app import app, db, models
from models import *
@app.route('/')
def test():
included_parts = db.session.query(
Part.sub_part,
Part.part,
Part.quantity).\
filter(Part.part=="our part").\
cte(name="included_parts", recursive=True)
incl_alias = db.aliased(included_parts, name="pr")
parts_alias = db.aliased(Part, name="p")
included_parts = included_parts.union_all(
db.session.query(
parts_alias.sub_part,
parts_alias.part,
parts_alias.quantity).\
filter(parts_alias.part==incl_alias.c.sub_part)
)
q = db.session.query(
included_parts.c.sub_part,
db.func.sum(included_parts.c.quantity).
label('total_quantity')
).\
group_by(included_parts.c.sub_part).all()
return 'test complete'
但这给出了一个错误:
OperationalError: (sqlite3.OperationalError) near "WITH": syntax error [SQL: u'WITH RECURSIVE included_parts(sub_part, part, quantity) AS \n(SELECT parts.sub_part AS sub_part, parts.part AS part, parts.quantity AS quantity \nFROM parts \nWHERE parts.part = ? UNION ALL SELECT p.sub_part AS p_sub_part, p.part AS p_part, p.quantity AS p_quantity \nFROM parts AS p, included_parts AS pr \nWHERE p.part = pr.sub_part)\n SELECT included_parts.sub_part AS included_parts_sub_part, sum(included_parts.quantity) AS total_quantity \nFROM included_parts GROUP BY included_parts.sub_part'] [parameters: ('our part',)]
生成的查询(从错误消息中复制粘贴)如下所示:
WITH RECURSIVE included_parts(sub_part, part, quantity) AS \n(SELECT parts.sub_part AS sub_part, parts.part AS part, parts.quantity AS quantity \nFROM parts \nWHERE parts.part = ? UNION ALL SELECT p.sub_part AS p_sub_part, p.part AS p_part, p.quantity AS p_quantity \nFROM parts AS p, included_parts AS pr \nWHERE p.part = pr.sub_part)\n SELECT included_parts.sub_part AS included_parts_sub_part, sum(included_parts.quantity) AS total_quantity \nFROM included_parts GROUP BY included_parts.sub_part
格式化(为了便于阅读,在不同的地方换行):
WITH RECURSIVE included_parts(sub_part, part, quantity) AS (
SELECT parts.sub_part AS sub_part, parts.part AS part, parts.quantity AS quantity
FROM parts
WHERE parts.part = ?
UNION ALL
SELECT p.sub_part AS p_sub_part, p.part AS p_part, p.quantity AS p_quantity
FROM parts AS p, included_parts AS pr
WHERE p.part = pr.sub_part
)
SELECT included_parts.sub_part AS included_parts_sub_part, sum(included_parts.quantity) AS total_quantity
FROM included_parts
GROUP BY included_parts.sub_part
并且,为了比较,这里是纯 PostgreSQL 查询,sqlalchemy 文档 link 到:
WITH RECURSIVE included_parts(sub_part, part, quantity) AS (
SELECT sub_part, part, quantity FROM parts WHERE part = 'our_product'
UNION ALL
SELECT p.sub_part, p.part, p.quantity
FROM included_parts pr, parts p
WHERE p.part = pr.sub_part
)
SELECT sub_part, SUM(quantity) as total_quantity
FROM included_parts
GROUP BY sub_part
我能看到的 Postgre 查询(我认为应该有效)和我生成的查询之间的唯一区别是:
- 所有额外的 "AS" 语句(
SELECT parts.sub_part AS sub_part
对比 SELECT sub_part
)
- 格式不同(生成的查询在奇怪的地方有换行符 - 例如,
UNION ALL
和 SELECT
之间没有换行符)
但是,据我所知,这些都不会导致语法错误...
我还尝试将 Postgre 查询作为原始 SQL 执行(尽管 SQLAlchemy 显然使用 sqlite3,但仍然):
query = db.engine.execute(\
'''WITH RECURSIVE included_parts(sub_part, part, quantity) AS (
SELECT sub_part, part, quantity FROM parts WHERE part = 'our_product'
UNION ALL
SELECT p.sub_part, p.part, p.quantity
FROM included_parts pr, parts p
WHERE p.part = pr.sub_part
)
SELECT sub_part, SUM(quantity) as total_quantity
FROM included_parts
GROUP BY sub_part''').all()
但我仍然遇到语法错误。
OperationalError: (sqlite3.OperationalError) near "WITH": syntax error [SQL: "WITH RECURSIVE included_parts(sub_part, part, quantity) AS (\nSELECT sub_part, part, quantity FROM parts WHERE part = 'our_product'\nUNION ALL\nSELECT p.sub_part, p.part, p.quantity\nFROM included_parts pr, parts p\nWHERE p.part = pr.sub_part\n)\nSELECT sub_part, SUM(quantity) as total_quantity\nFROM included_parts\nGROUP BY sub_part"]
我还尝试重新格式化生成的查询并将其作为原始 SQL 执行,结果相似。
最后,我尝试在 SQLite 中编写查询并执行它:
WITH RECURSIVE included_parts(sub_part, part, quantity) AS (
SELECT sub_part, part, quantity FROM parts WHERE part="our_product"
UNION ALL
SELECT parts.sub_part, parts.part, parts.quantity FROM parts, included_parts WHERE parts.part=included_parts.sub_part
)
SELECT sub_part, SUM(quantity) AS total_quantity
FROM included_parts
GROUP BY sub_part
这也会引发语法错误。
在这一点上,我不太确定该怎么做...似乎即使 WITH
具有正确语法的查询仍然会抛出错误。根据文档和此处 (_ 的回答,我知道 Sqlalchemy 支持递归 CTE 查询。老实说,我不知道为什么所有这些查询都被认为语法错误。我的 python 代码与文档中的示例几乎相同。
我需要为 WITH RECURSIVE
安装一些东西才能在 SQLAlchemy 中工作吗?我的语法真的错了吗?几乎迷失在这里,任何帮助表示赞赏。
(正在编辑以将其返回首页。我希望我可以说我已经取得了一些进展,但我现在真的不知道该怎么做。这是 PostgreSQL vs SQLite 问题?有没有人有我正在尝试做的工作示例,我可以看看?)
问题是您 运行 旧版本的 sqlite3(如#sqlalchemy 中所讨论);你有 3.8.2 并且在 3.8.3 中添加了 CTE 支持。
我正在尝试重现在 SqlAlchemy 文档页面上找到的 this 查询。在 models.py
中设置 Part
class 之后,这就是我所拥有的:
from app import app, db, models
from models import *
@app.route('/')
def test():
included_parts = db.session.query(
Part.sub_part,
Part.part,
Part.quantity).\
filter(Part.part=="our part").\
cte(name="included_parts", recursive=True)
incl_alias = db.aliased(included_parts, name="pr")
parts_alias = db.aliased(Part, name="p")
included_parts = included_parts.union_all(
db.session.query(
parts_alias.sub_part,
parts_alias.part,
parts_alias.quantity).\
filter(parts_alias.part==incl_alias.c.sub_part)
)
q = db.session.query(
included_parts.c.sub_part,
db.func.sum(included_parts.c.quantity).
label('total_quantity')
).\
group_by(included_parts.c.sub_part).all()
return 'test complete'
但这给出了一个错误:
OperationalError: (sqlite3.OperationalError) near "WITH": syntax error [SQL: u'WITH RECURSIVE included_parts(sub_part, part, quantity) AS \n(SELECT parts.sub_part AS sub_part, parts.part AS part, parts.quantity AS quantity \nFROM parts \nWHERE parts.part = ? UNION ALL SELECT p.sub_part AS p_sub_part, p.part AS p_part, p.quantity AS p_quantity \nFROM parts AS p, included_parts AS pr \nWHERE p.part = pr.sub_part)\n SELECT included_parts.sub_part AS included_parts_sub_part, sum(included_parts.quantity) AS total_quantity \nFROM included_parts GROUP BY included_parts.sub_part'] [parameters: ('our part',)]
生成的查询(从错误消息中复制粘贴)如下所示:
WITH RECURSIVE included_parts(sub_part, part, quantity) AS \n(SELECT parts.sub_part AS sub_part, parts.part AS part, parts.quantity AS quantity \nFROM parts \nWHERE parts.part = ? UNION ALL SELECT p.sub_part AS p_sub_part, p.part AS p_part, p.quantity AS p_quantity \nFROM parts AS p, included_parts AS pr \nWHERE p.part = pr.sub_part)\n SELECT included_parts.sub_part AS included_parts_sub_part, sum(included_parts.quantity) AS total_quantity \nFROM included_parts GROUP BY included_parts.sub_part
格式化(为了便于阅读,在不同的地方换行):
WITH RECURSIVE included_parts(sub_part, part, quantity) AS (
SELECT parts.sub_part AS sub_part, parts.part AS part, parts.quantity AS quantity
FROM parts
WHERE parts.part = ?
UNION ALL
SELECT p.sub_part AS p_sub_part, p.part AS p_part, p.quantity AS p_quantity
FROM parts AS p, included_parts AS pr
WHERE p.part = pr.sub_part
)
SELECT included_parts.sub_part AS included_parts_sub_part, sum(included_parts.quantity) AS total_quantity
FROM included_parts
GROUP BY included_parts.sub_part
并且,为了比较,这里是纯 PostgreSQL 查询,sqlalchemy 文档 link 到:
WITH RECURSIVE included_parts(sub_part, part, quantity) AS (
SELECT sub_part, part, quantity FROM parts WHERE part = 'our_product'
UNION ALL
SELECT p.sub_part, p.part, p.quantity
FROM included_parts pr, parts p
WHERE p.part = pr.sub_part
)
SELECT sub_part, SUM(quantity) as total_quantity
FROM included_parts
GROUP BY sub_part
我能看到的 Postgre 查询(我认为应该有效)和我生成的查询之间的唯一区别是:
- 所有额外的 "AS" 语句(
SELECT parts.sub_part AS sub_part
对比SELECT sub_part
) - 格式不同(生成的查询在奇怪的地方有换行符 - 例如,
UNION ALL
和SELECT
之间没有换行符)
但是,据我所知,这些都不会导致语法错误... 我还尝试将 Postgre 查询作为原始 SQL 执行(尽管 SQLAlchemy 显然使用 sqlite3,但仍然):
query = db.engine.execute(\
'''WITH RECURSIVE included_parts(sub_part, part, quantity) AS (
SELECT sub_part, part, quantity FROM parts WHERE part = 'our_product'
UNION ALL
SELECT p.sub_part, p.part, p.quantity
FROM included_parts pr, parts p
WHERE p.part = pr.sub_part
)
SELECT sub_part, SUM(quantity) as total_quantity
FROM included_parts
GROUP BY sub_part''').all()
但我仍然遇到语法错误。
OperationalError: (sqlite3.OperationalError) near "WITH": syntax error [SQL: "WITH RECURSIVE included_parts(sub_part, part, quantity) AS (\nSELECT sub_part, part, quantity FROM parts WHERE part = 'our_product'\nUNION ALL\nSELECT p.sub_part, p.part, p.quantity\nFROM included_parts pr, parts p\nWHERE p.part = pr.sub_part\n)\nSELECT sub_part, SUM(quantity) as total_quantity\nFROM included_parts\nGROUP BY sub_part"]
我还尝试重新格式化生成的查询并将其作为原始 SQL 执行,结果相似。
最后,我尝试在 SQLite 中编写查询并执行它:
WITH RECURSIVE included_parts(sub_part, part, quantity) AS (
SELECT sub_part, part, quantity FROM parts WHERE part="our_product"
UNION ALL
SELECT parts.sub_part, parts.part, parts.quantity FROM parts, included_parts WHERE parts.part=included_parts.sub_part
)
SELECT sub_part, SUM(quantity) AS total_quantity
FROM included_parts
GROUP BY sub_part
这也会引发语法错误。
在这一点上,我不太确定该怎么做...似乎即使 WITH
具有正确语法的查询仍然会抛出错误。根据文档和此处 (_ 的回答,我知道 Sqlalchemy 支持递归 CTE 查询。老实说,我不知道为什么所有这些查询都被认为语法错误。我的 python 代码与文档中的示例几乎相同。
我需要为 WITH RECURSIVE
安装一些东西才能在 SQLAlchemy 中工作吗?我的语法真的错了吗?几乎迷失在这里,任何帮助表示赞赏。
(正在编辑以将其返回首页。我希望我可以说我已经取得了一些进展,但我现在真的不知道该怎么做。这是 PostgreSQL vs SQLite 问题?有没有人有我正在尝试做的工作示例,我可以看看?)
问题是您 运行 旧版本的 sqlite3(如#sqlalchemy 中所讨论);你有 3.8.2 并且在 3.8.3 中添加了 CTE 支持。