使用 Python 逐行比较两个文本文件

Question

我有两个文本文件要比较。第一个文件包含独特的项目，第二个文件包含相同的项目但重复了多次。我想看看第二个文件中每一行重复了多少次。这是我写的：

import os
import sys

f1 = open('file1.txt')  # this has the 27 unique lines, 
f1data = f1.readlines()

f2 = open('file2.txt')  # this has lines repeated various times, with a total of 11162 lines
f2data = f2.readlines()

sys.stdout = open("linecount.txt", "w")


for line1 in f1data:
    linecount = 0
    for line2 in f2data:
        if line1 in line2:
        linecount+=1

    print line2, crime

问题是，当我将行数加起来时，结果是 returns 11586，而不是 11162。行数增加的原因是什么？

是否有另一种使用 Python 获得线路频率输出的方法？

Answer 1

https://docs.python.org/2.7/reference/expressions.html#in:

For the Unicode and string types, x in y is true if and only if x is a substring of y.

而不是

    if line1 in line2:

我想你是想写

    if line1 == line2:

或者替换整个

for line2 in f2data:
    if line1 in line2:
        linecount+=1

阻止

if line1 in f2data:
    linecount += 1

Answer 2

即使我们稍微更改一下代码，它也不起作用。我从这段代码中得到了一些更好的结果。

>> import os
>> import sys

>> f1 = open('hmd4.csv')   
>> f2 = open('svm_words.txt')  

>> linecount = 0

>> for word1 in f1.read().split("."):
>>     for word2 in f2.read().split("\n"):
>>         if word1 in word2:
>>             linecount+=1 
>>             print (linecount)

使用 Python 逐行比较两个文本文件

Using Python to Compare Two Text Files Line by Line

python

frequency

count

line