如何将 2 个具有不同 where 子句的 oracle 查询合并为 1 个查询

Question

我有以下 2 个具有不同 where 条件的 oracle 查询（条件相同的某些条件）。是否可以将这 2 个查询合并为 1 个查询？查询在这里

不同条件：TX_TYPE, TX_STATUS

常见条件：SUBSCRIBER_ID, MERCHANT_ID, IS_TAXABLE, TX_DATE

查询 1:

select sum(t.AMOUNT) Amt1
  from RS_TRANSACTION_LOG t, RS_MERCHANT m
 where t.SUBSCRIBER_ID = 11338329
   and t.MERCHANT_ID = m.MERCHANT_ID
   and t.TX_TYPE = '1'
   and t.TX_STATUS in (5, 42)
   and m.IS_TAXABLE = 'Y'
   and TX_DATE between to_date('11/01/2015 00:00:00','MM/dd/YYYY HH24:MI:SS')
                   and to_date('11/30/2015 23:59:59','MM/dd/YYYY HH24:MI:SS');

查询 2:

select sum(t.AMOUNT) Amt2
  from RS_TRANSACTION_LOG t, RS_MERCHANT m
 where t.SUBSCRIBER_ID = 11338329
   and t.MERCHANT_ID = m.MERCHANT_ID
   and t.TX_TYPE = '5'
   and t.TX_STATUS = 5
   and m.IS_TAXABLE = 'Y'
   and TX_DATE between to_date('11/01/2015 00:00:00','MM/dd/YYYY HH24:MI:SS')
                   and to_date('11/30/2015 23:59:59','MM/dd/YYYY HH24:MI:SS');

Answer 1

如何使用 OR 组合条件和 CASE 分隔金额：

select sum(case when t.TX_TYPE = '1' and t.TX_STATUS in (5,42) then t.AMOUNT else 0 end) Amt1,
       sum(case when t.TX_TYPE = '5' and t.TX_STATUS = 5 then t.AMOUNT else 0 end) Amt2
from   RS_TRANSACTION_LOG t,
       RS_MERCHANT m
where  t.SUBSCRIBER_ID=11338329
and    t.MERCHANT_ID=m.MERCHANT_ID
and    ((t.TX_TYPE = '1' and t.TX_STATUS in (5,42)) or
        (t.TX_TYPE='5' and t.TX_STATUS = '5'))
and    m.IS_TAXABLE='Y'
and    TX_DATE between
       to_date('11/01/2015 00:00:00','MM/dd/YYYY HH24:MI:SS') and
       to_date('11/30/2015 23:59:59','MM/dd/YYYY HH24:MI:SS');

如何将 2 个具有不同 where 子句的 oracle 查询合并为 1 个查询

How to combine 2 oracle queries with differrent where clauseses into 1 query

sql

oracle

where