将浏览对话框中选择的文件文本传输到 Powershell 中的文本输入字段

Question

第一次尝试在 Powershell v3 中自定义对话框。我想在表单中添加一个浏览按钮。我有它，所以它显示了浏览按钮，但我似乎无法弄清楚我们从 OpenFileDialog 对象中获取文件名并将其显示在 objTextBox 字段中的部分。我已经研究过，但似乎找不到任何解释这部分过程的文章。

$objTextBox = New-Object System.Windows.Forms.TextBox
$objTextBox.Name = 'Text1' 
$objTextBox.Location = New-Object System.Drawing.Size(10,40) 
$objTextBox.Size = New-Object System.Drawing.Size(260,20) 
$objForm.Controls.Add($objTextBox) 



#File Browser Code.

    $FileBrowser = New-Object System.Windows.Forms.OpenFileDialog -Property @{
        InitialDirectory = [Environment]::GetFolderPath('Desktop')
    }


$browse_button = New-Object system.Windows.Forms.Button
$browse_button.Text = "Choose...."
$browse_button.Location = New-Object System.Drawing.Size(10,75) 
$browse_button.Size = New-Object System.Drawing.Size(100,27) 
$browse_button.Add_Click({[void]$FileBrowser.ShowDialog()})
$objForm.Controls.Add($browse_button)

Answer 1

我想我会稍微不同地处理它。我会制作一个显示“浏览文件”对话框并输出字符串的函数（我恰好随身携带）。然后为 Add_Click 设置文本框的值 = 函数。类似于：

Function Get-FilePath{
[CmdletBinding()]
Param(
    [String]$Filter = "|*.*",
    [String]$InitialDirectory = "C:\")

    [void][System.Reflection.Assembly]::LoadWithPartialName("System.windows.forms")
    $OpenFileDialog = New-Object System.Windows.Forms.OpenFileDialog
    $OpenFileDialog.initialDirectory = $InitialDirectory
    $OpenFileDialog.filter = $Filter
    [void]$OpenFileDialog.ShowDialog()
    $OpenFileDialog.filename
}

$objTextBox = New-Object System.Windows.Forms.TextBox
$objTextBox.Name = 'Text1' 
$objTextBox.Location = New-Object System.Drawing.Size(10,40) 
$objTextBox.Size = New-Object System.Drawing.Size(260,20) 
$objForm.Controls.Add($objTextBox)
$browse_button = New-Object system.Windows.Forms.Button
$browse_button.Text = "Choose...."
$browse_button.Location = New-Object System.Drawing.Size(10,75) 
$browse_button.Size = New-Object System.Drawing.Size(100,27) 
$browse_button.Add_Click({$objTextBox.Text = Get-FilePath -InitialDirectory "$env:UserProfile\Desktop"})
$objForm.Controls.Add($browse_button) 
$browse_button.Text = "Choose...."
$browse_button.Location = New-Object System.Drawing.Size(10,75) 
$browse_button.Size = New-Object System.Drawing.Size(100,27) 
$browse_button.Add_Click({[void]$FileBrowser.ShowDialog()})
$objForm.Controls.Add($browse_button)

将浏览对话框中选择的文件文本传输到 Powershell 中的文本输入字段

Transfering file chosen text in Browse Dialog box to the Text Input field in Powershell

powershell

file