我怎样才能让程序重复而不需要用户关闭 shell？

Question

我无法找到让用户重复代码而无需退出 shell 的方法。这是我目前所拥有的。

import random
randomNum = random.randint(1, 10)
start = True
answer = int(raw_input("Try to guess a random number between 1 and 10. "))
#The code cant be both less than and greater than. The or function allows this 
while (answer > randomNum) or (answer < randomNum):
    if (answer == randomNum + 1):
        print "Super Close"
        answer = int(raw_input("Try to guess a random number between 1 and 10. "))
#First one
    elif (answer == randomNum + 2):
        print "Pretty Close"
        answer = int(raw_input("Try to guess a random number between 1 and 10. "))
#Second one
    elif (answer == randomNum + 3):
        print "Fairly Close"
        answer = int(raw_input("Try to guess a random number between 1 and 10. "))
#Third one
    elif (answer == randomNum + 4):
        print "Not Really Close"
        answer = int(raw_input("Try to guess a random number between 1 and 10. "))
#Fourth one
    elif (answer == randomNum + 5):
        print "Far"
        answer = int(raw_input("Try to guess a random number between 1 and 10. "))
#Fifth one
    elif (answer == randomNum - 5):
        print "Far"
        answer = int(raw_input("Try to guess a random number between 1 and 10. "))
#Sixth one
    elif (answer == randomNum - 4):
        print "Not Really Close"
        answer = int(raw_input("Try to guess a random number between 1 and 10. "))
#Seventh one
    elif (answer == randomNum - 3):
        print "Fairly Close"
        answer = int(raw_input("Try to guess a random number between 1 and 10. "))
#Eighth one
    elif (answer == randomNum - 2):
        print "Pretty Close"
        answer = int(raw_input("Try to guess a random number between 1 and 10. "))
#Nineth one
    elif (answer == randomNum - 1):
        print "Super Close"
        answer = int(raw_input("Try to guess a random number between 1 and 10. "))
#Tenth one
else:
    print "Good Job!"
    print randomNum
    if (start == True):
        answerAgain = raw_input("Do you want to restart this program ? ")
        if answerAgain == ("Yes", "yes", "ya", "Ya", "Okay", "Sure", "Si", "Start"):
        #Empty space because I don't know what to put in here.

        else:
            print "See ya next time!"

我想知道如何将所有这些代码应用到一个变量或重复执行，而无需编写 50 次。

Answer 1

将代码放入 while 循环以重复它。

start = True

while start:

    # code

    if answerAgain.lower() in ('no', 'niet', 'bye'):
        start = False

Answer 2

我建议将整个事情包含在一个 while 循环中。

start = True
while start == True:
    """your code here"""
    answerAgain = raw_input("Do you want to restart this program ? ")
        if answerAgain == ("Yes", "yes", "ya", "Ya", "Okay", "Sure", "Si", "Start"):
            start = True
        else:
            start = False

这样，如果 start == True，您的整个代码将再次运行。

我还建议您使用列表进行回复。

responses = ["Super Close", "Pretty Close", "Fairly Close", "Not Really Close", "Far"]

这样您就可以使用差异映射到适当的响应：

print responses[abs(answer - randomNum) - 1]

Answer 3

如果您使用用户提供的数字和您的随机数之间的绝对值，您只需记录一半的案例（即 -1 和 +1 得到相同的处理）。
与其在每个案例之后询问他们的新答案，不如将此代码移至主循环的顶部，因为它是程序开始时的请求，并遵循所有 'wrong' 个答案。
对于用法，您可能希望将所有 'word' 答案转换为小写，因为在这种情况下大小写似乎无关紧要。
您可以使用quit()彻底退出程序。

所以可能是这样的：

import random

while(True):
    randomNum = random.randint(1, 10)
    answer = 0
    while abs(answer - randomNum) > 0:
        answer = int(input("Try to guess a random number between 1 and 10. "))
        if abs(answer - randomNum) == 1:
            print("Super Close")
        elif abs(answer - randomNum) == 2:
            print("Pretty Close")
        # the other cases ...

    # gets here if abs(answer - randonNum) == 0, i.e. they guessed right
    print("Good Job!", randomNum)
    answerAgain = input("Do you want to restart this program ? ")
    if answerAgain.lower() in ["yes", "ya", "y", "okay", "sure", "si", "start"]:
        pass
    else:
        print("See ya next time!")
        quit()

我怎样才能让程序重复而不需要用户关闭 shell？

How can I get the program to repeat without having the user have to close out of the shell?

python

random

shell

numbers

generator