重新排序文本文件 - Python
Re-ordering text file - Python
我必须重新排序输入文件,然后将输出打印到新文件。
这是输入文件:
The first line never changes.
The second line was a bit much longer.
The third line was short.
The fourth line was nearly the longer line.
The fifth was tiny.
The sixth line is just one line more.
The seventh line was the last line of the original file.
输出文件应该是这样的:
The first line never changes.
The seventh line was the last line of the original file.
The second line was a bit much longer.
The sixth line is just one line more.
The third line was short.
The fifth was tiny.
The fourth line was nearly the longer line.
我已经有代码可以反转输入文件并将其打印到输出文件,如下所示
ifile_name = open(ifile_name, 'r')
lines = ifile_name.readlines()
ofile_name = open(ofile_name, "w")
lines[-1] = lines[-1].rstrip() + '\n'
for line in reversed(lines):
ofile_name.write(line)
ifile_name.close()
ofile_name.close()
有没有办法在保留我的反向代码的同时在文本文件中获得所需的格式?
比如打印输入文件的第一行,然后反转打印该行,打印输入文件的第二行,然后反转打印该行等
抱歉,如果这看起来不清楚,我是 Python 和堆栈溢出的新手。
提前致谢。
ifile_name = "hello/input.txt"
ofile_name = "hello/output.txt"
ifile_name = open(ifile_name, 'r')
lines = ifile_name.readlines()
ofile_name = open(ofile_name, "w")
lines[-1] = lines[-1].rstrip() + '\n'
start = 0
end = len(lines) - 1
while start < end:
ofile_name.write(lines[start])
ofile_name.write(lines[end])
start += 1
end -= 1
if start == end:
ofile_name.write(lines[start])
ifile_name.close()
ofile_name.close()
使用两个枢轴start
和end
指向写入文件的那一行。
一旦start
== end
,将中间行写入文件
如果您不关心生成的列表,我相信这是一个非常优雅的解决方案。
with open("ifile_name","r") as f:
init_list=f.read().strip().splitlines()
with open("result.txt","a") as f1:
while True:
try:
f1.write(init_list.pop(0)+"\n")
f1.write(init_list.pop()+"\n")
except IndexError:
break
我必须重新排序输入文件,然后将输出打印到新文件。
这是输入文件:
The first line never changes.
The second line was a bit much longer.
The third line was short.
The fourth line was nearly the longer line.
The fifth was tiny.
The sixth line is just one line more.
The seventh line was the last line of the original file.
输出文件应该是这样的:
The first line never changes.
The seventh line was the last line of the original file.
The second line was a bit much longer.
The sixth line is just one line more.
The third line was short.
The fifth was tiny.
The fourth line was nearly the longer line.
我已经有代码可以反转输入文件并将其打印到输出文件,如下所示
ifile_name = open(ifile_name, 'r')
lines = ifile_name.readlines()
ofile_name = open(ofile_name, "w")
lines[-1] = lines[-1].rstrip() + '\n'
for line in reversed(lines):
ofile_name.write(line)
ifile_name.close()
ofile_name.close()
有没有办法在保留我的反向代码的同时在文本文件中获得所需的格式?
比如打印输入文件的第一行,然后反转打印该行,打印输入文件的第二行,然后反转打印该行等
抱歉,如果这看起来不清楚,我是 Python 和堆栈溢出的新手。
提前致谢。
ifile_name = "hello/input.txt"
ofile_name = "hello/output.txt"
ifile_name = open(ifile_name, 'r')
lines = ifile_name.readlines()
ofile_name = open(ofile_name, "w")
lines[-1] = lines[-1].rstrip() + '\n'
start = 0
end = len(lines) - 1
while start < end:
ofile_name.write(lines[start])
ofile_name.write(lines[end])
start += 1
end -= 1
if start == end:
ofile_name.write(lines[start])
ifile_name.close()
ofile_name.close()
使用两个枢轴start
和end
指向写入文件的那一行。
一旦start
== end
,将中间行写入文件
如果您不关心生成的列表,我相信这是一个非常优雅的解决方案。
with open("ifile_name","r") as f:
init_list=f.read().strip().splitlines()
with open("result.txt","a") as f1:
while True:
try:
f1.write(init_list.pop(0)+"\n")
f1.write(init_list.pop()+"\n")
except IndexError:
break