使以下C++代码简洁高效

Question

我有一个包含 52 个元素的数组，每 13 个元素的值都需要从 1-13

示例：

// Referring arr to an array of 52 elements


arr[0] = 1;
arr[1] = 2;
arr[2] = 3;
...
arr[10] = 11;
arr[11]] = 12;
arr[12] = 13;
arr[13] = 1;

and so on...

我想出的代码有4个for循环，每次从1-13循环，我觉得效率很低。

int j = 1;  
    for(int i = 0; i < 13; i++){
        deck[i].suit = 'H';
        deck[i].value = j;
        j++;
    }
    j = 1;
    for(int i = 13; i < 26; i++){
        deck[i].suit = 'D';
        deck[i].value = j;
        j++;
    }
    j = 1;
    for(int i = 26; i < 39; i++){
        deck[i].suit = 'S';
        deck[i].value = j;
        j++;
    }
    j = 1;
    for(int i = 39; i <= 51; i++){
        deck[i].suit = 'C';
        deck[i].value = j;
        j++;
    }

Answer 1

你说得对，你可以做得更好：

char suits[] = "HDSC";

for (int i = 0; i < 52; ++i) {
    deck[i].value = (i % 13) + 1; // this is a number from [1,13]
    deck[i].suit = suits[i / 13]; // i/13 is a number from [0,4)
}

使以下C++代码简洁高效

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