传递列表以在 MVC 中查看

Question

我正在将列表值传递到我的视图。但是我收到 "The model item passed into the dictionary is of type 'System.Collections.Generic.List" 的错误。这是我的控制器操作：

public ActionResult Index()
    {
        Test t = new Test();
        List<Customer> myList= t.GetData();
        return View(myList);
    }

视图如下：

@model List<AsyncActions.Models.Test>
@{
  ViewBag.Title = "Index";
}

<h2>Index</h2>
<table border="1" cellpadding="4">
    @foreach (var row in Model)
    {
    <tr>
        @*<td>@row."CustomerID"</td>
        <td>@row."CustomerCode"</td>*@
    </tr>
}

这是我的模型：

namespace AsyncActions.Models
{
public class Test
{
    public List<Customer> GetData()
    {
        try
        {
            Customer c = new Customer();
            List<Customer> cst = new List<Customer>();
            for (int i = 0; i < 10; i++)
            {                    
                c.CustomerID = i;
                c.CustomerCode = "CST"+i;
                cst.Add(c);
            }
            return cst;
        }
        catch (Exception)
        {
            throw new NotImplementedException();
        }

    }
}
public class Customer
{
    public int CustomerID { get; set; }
    public string CustomerCode { get; set; }
}
}

我已经尝试从视图中删除 List<>。当我这样做时，我收到错误 "foreach statement cannot operate on variables of type 'AsyncActions.Models.Test' because 'AsyncActions.Models.Test' does not contain a public definition for 'GetEnumerator"。我已经尝试了很多东西。我检查了这个 link ，但这并没有解决我的问题。我无法找出我错过了什么。非常感谢任何帮助。

Answer 1

您的视图模型应该是

@model List<Customer>

Answer 2

将您的 @model 更改为 @model IEnumerable<Customer>

@model IEnumerable<Customer>
@{
  ViewBag.Title = "Index";
}

<h2>Index</h2>
<table border="1" cellpadding="4">
    @foreach (var row in Model)
    {
    <tr>
        @*<td>@row."CustomerID"</td>
        <td>@row."CustomerCode"</td>*@
    </tr>
}

Answer 3

您应该将模型的定义更改为：

@model List<Customer>
@{
  ViewBag.Title = "Index";
}

<h2>Index</h2>
<table border="1" cellpadding="4">
    @foreach (var row in Model)
    {
    <tr>
        @*<td>@row."CustomerID"</td>
        <td>@row."CustomerCode"</td>*@
    </tr>
}

Answer 4

在你看来使用这个应该可以解决问题：

@model List<Customer>