使用顺序选项时，Sequelize 生成无效的 SQL

Question

当我在 #findAll 中使用订单选项时，它会生成 SQL:

SELECT
  `id`, `first_name` AS `firstName`,
  `last_name` AS `lastName` FROM `customers` AS `Customer`
ORDER BY `Customer`.`firstName` DESC;

但是这个 SQL 导致错误：

ER_BAD_FIELD_ERROR: Unknown column 'Customer.firstName' in 'order clause'

代码示例：

var Customer = sequelize.define("Customer", {
  id: {
    type: Sequelize.INTEGER({unsigned: true}),
    primaryKey: true
  },
  firstName: {
    type: Sequelize.STRING(32),
    field: "first_name"
  },
  lastName: {
    type: Sequelize.STRING(32),
    field: "last_name"
  }
}, {
  name: {
    singular: "customer",
    plural: "customers"
  },
  tableName: "customers",
  timestamps: false,
  underscored: true
});

Customer.findAll({
  order: [["firstName", "DESC"]]
}).then(function(list) {
  console.log(list);
}).catch(function(err) {
  console.log(err);
});

Mysql: 5.6.20

续集：3.14.2

这个问题有什么解决方案吗？

Answer 1

使用order: [["first_name", "DESC"]]； ORDER BY 查看列名，而不是您的 SELECT 别名 firstName。

使用顺序选项时，Sequelize 生成无效的 SQL

Sequelize generates a not working SQL when use order option

mysql

sql-order-by

node.js

sequelize.js