Moment.js - 获取两个生日的年月日差值

Question

我正在寻找一种使用 momentjs 解析两个日期以显示差异的方法。

我想要它的格式："X years, Y months, Z days"。

多年来，moment 库和模运算符运行良好。但就目前而言，这是另一个故事，因为我不想自己处理闰年之类的事情。到目前为止，我脑子里的逻辑是：

var a = moment([2015, 11, 29]);
var b = moment([2007, 06, 27]);

var years = a.diff(b, 'years');
var months = a.diff(b, 'months') % 12;
var days = a.diff(b, 'days');
// Abit stuck here as leap years, and difference in number of days in months. 
// And a.diff(b, 'days') returns total number of days.
return years + '' + months + '' + days;

Answer 1

您可以获得年份差异并将其添加到初始日期；然后得到月份的差异并将其再次添加到初始日期。

这样一来，您现在可以轻松获得天数差异，同时避免使用取模运算符。

Example Here

var a = moment([2015, 11, 29]);
var b = moment([2007, 06, 27]);

var years = a.diff(b, 'year');
b.add(years, 'years');

var months = a.diff(b, 'months');
b.add(months, 'months');

var days = a.diff(b, 'days');

console.log(years + ' years ' + months + ' months ' + days + ' days');
// 8 years 5 months 2 days

我不知道有更好的内置方法来实现这一点，但这种方法似乎很有效。

Answer 2

Moment.js 也有 duration 对象。片刻定义为单个时间点，而持续时间定义为基本上您想要的时间长度。

var a = moment([2015, 11, 29]);
var b = moment([2007, 06, 27]);

var diffDuration = moment.duration(a.diff(b));

console.log(diffDuration.years()); // 8 years
console.log(diffDuration.months()); // 5 months
console.log(diffDuration.days()); // 2 days

@Josh 的建议可能有效，但绝对不是计算 2 时刻差异的正确方法。

Answer 3

以上解决方案不适用于 momentjs 2.19.1

然后参考 Date of Joining calculation not working with moment 2.19.1 我已经使用 momentjs 2.19.1.

的最新解决方案实现了新的解决方案

需要的 npm 包:

"moment": "^2.19.4",

"moment-duration-format": "^1.3.0",

"react-moment": "^0.6.8",

在 reactjs 中导入以下内容:

 import moment from "moment";
 import Moment from "react-moment";
 import momentDurationFormatSetup from "moment-duration-format";

var DOJ = moment([work_data.joining_date]).format("YYYY,MM,DD");      
var today = moment().format("YYYY,MM,DD");      
var totalMonths =  parseInt(moment(today).diff(moment(DOJ), 'months'));      
var totalDuration = moment.duration(totalMonths, "months").format();      
if(totalDuration.search('1y') > -1) {
   totalDuration = totalDuration.replace("1y", "1 Year,");
} else {
   totalDuration = totalDuration.replace("y", " Years,");
}

if(totalDuration.search('1m') > -1){
  totalDuration = totalDuration.replace("1m", "1 Month");
} else {
  totalDuration = totalDuration.replace("m", " Months");
}

console.log(totalDuration);

Answer 4

这是另一个答案。使用年龄计算器验证

function calculateAge(){
    ageText = jQuery("#dob").closest(".form-group").find(".age-text");
    ageText.text("");
    level2.dob = jQuery("#dob").val();
    if(!level2.dob) return;
    level2.mdob= moment(level2.dob, 'DD-MM-YYYY');
    if(!level2.mdob.isValid()){
        alert("Invalid date format");
        return;
    }
    level2.targetDate = moment();//TODO: Fill in the target date
    level2.months = level2.targetDate.diff(level2.mdob, 'months'); // Calculate the months
    let years = parseInt(level2.months/12); // A year has 12 months irrespective or leap year or not
    let balanceMonths = level2.months%12; // The balance gives the number of months 
    let days;
    if(!balanceMonths){ // If no balance months, then the date selected lies in the same month
        months = 0; // so months = 0
        days = level2.targetDate.diff(level2.mdob, 'days'); // only the days difference
    }else{
    months = balanceMonths;
    dob_date = level2.mdob.date();
    target_month = level2.targetDate.month();
    construct_date = moment().month(target_month).date(dob_date);
    days = level2.targetDate.diff(construct_date, 'days')+1; // There might be one day missed out. Not sure on UTC
}

ageText = years +" years " + months+ " months " + days +" days";
}

Answer 5

我刚刚将转换为函数并添加了小时、分钟和秒也是。

 function diffYMDHMS(date1, date2) {

    let years = date1.diff(date2, 'year');
    date2.add(years, 'years');

    let months = date1.diff(date2, 'months');
    date2.add(months, 'months');

    let days = date1.diff(date2, 'days');
    date2.add(days, 'days');

    let hours = date1.diff(date2, 'hours');
    date2.add(hours, 'hours');

    let minutes = date1.diff(date2, 'minutes');
    date2.add(minutes, 'minutes');

    let seconds = date1.diff(date2, 'seconds');

    console.log(years + ' years ' + months + ' months ' + days + ' days ' + hours + ' 
    hours ' + minutes + ' minutes ' + seconds + ' seconds'); 

    return { years, months, days, hours, minutes, seconds};
}

Answer 6

使用这个

  var totalDays = endDate.diff(startDate, "days");

Answer 7

此处提供的所有解决方案对于某些测试用例均失败。所以我对接受的答案做了一些修改。

function getYMD(date1, date2) {
    const a = moment(date1);
    const b = moment(date2);
    var years = a.diff(b, 'year');
    b.add(years, 'years');

    const noOfDaysInb = b.daysInMonth();
    const noOfDaysIna = a.daysInMonth();
    let months = 0;
    if (noOfDaysInb > noOfDaysIna) {
        months = b.diff(a, "months");
        a.add(months, "months");
    } else {
        months = a.diff(b, 'months');
        b.add(months, 'months');
    }
    var days = a.diff(b, 'days');
    return {
        years: Math.abs(years),
        months: Math.abs(months),
        days: Math.abs(days),
    }
}

这是我能想到的最佳答案。

Moment.js - 获取两个生日的年月日差值

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