带有搜索过滤器的列表视图适配器 class 在搜索时未发送准确位置

Question

我正在尝试制作一个应用程序，该应用程序将在单击时显示 ListView 行的详细信息。我为搜索选项添加了一个过滤器和三个 EditText。

如果我使用所有选项进行搜索，我的应用程序会显示一个成员三次，这就是为什么我在 filter() 方法中注释掉两个条件。

但主要问题是，当我搜索成员时，它搜索得很好，但是当单击搜索结果时，ListView 行的位置似乎发生了变化。例如，如果我找到三个搜索结果，第一个在位置 0，第二个在位置 1，第三个在位置 2。

Listview 单击事件无需搜索即可正常工作。

我需要过滤之前的旧位置，以便通过 Intent 将其发送到另一个 Activity，这将为每个成员显示不同的数据。

ListViewAdapter.java class `

public class ListViewAdapter extends BaseAdapter {

// Declare Variables
Context mContext;
LayoutInflater inflater;
private List<WorldPopulation> worldpopulationlist = null;
private ArrayList<WorldPopulation> arraylist;

public ListViewAdapter(Context context, List<WorldPopulation> worldpopulationlist) {
    mContext = context;
    this.worldpopulationlist = worldpopulationlist;
    inflater = LayoutInflater.from(mContext);
    this.arraylist = new ArrayList<WorldPopulation>();
    this.arraylist.addAll(worldpopulationlist);
}

public class ViewHolder {
    TextView rank;
    TextView country;
    TextView population;
    ImageView flag;
}

@Override
public int getCount() {
    return worldpopulationlist.size();
}
@Override
public WorldPopulation getItem(int position) {
    return worldpopulationlist.get(position);
}

@Override
public long getItemId(int position) {
    return position;
}

public View getView(final int position, View view, final ViewGroup parent) {
    final ViewHolder holder;
    if (view == null) {
        holder = new ViewHolder();
        view = inflater.inflate(R.layout.listview_item, null);
        // Locate the TextViews in listview_item.xml
        holder.rank = (TextView) view.findViewById(R.id.rank);
        holder.country = (TextView) view.findViewById(R.id.country);
        holder.population = (TextView) view.findViewById(R.id.population);
        // Locate the ImageView in listview_item.xml
        holder.flag = (ImageView) view.findViewById(R.id.flag);
        view.setTag(holder);
    } else {
        holder = (ViewHolder) view.getTag();
    }
    // Set the results into TextViews
    holder.rank.setText(worldpopulationlist.get(position).getRank());
    holder.country.setText(worldpopulationlist.get(position)
          .getCountry());
    holder.population.setText(worldpopulationlist.get(position)
          .getPopulation());
    // Set the results into ImageView
    holder.flag.setImageResource(worldpopulationlist.get(position)
                    .getFlag());

    // Listen for ListView Item Click
    view.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View arg0) {
            Intent summaryIntent = new Intent(mContext,
                    SecondActivity.class);
            Bundle b = new Bundle();
            b.putInt("Integer", position);
            summaryIntent.putExtras(b);
            mContext.startActivity(summaryIntent);
            Toast.makeText(mContext, "Position:" + position,
                            Toast.LENGTH_SHORT).show();

           Intent intent = new Intent(mContext, SecondActivity.class);
           // Send single item click data to SingleItemView Class
           // depending on "position", for example

           // Pass all data rank
           //  intent.putExtra("rank",
           //      (worldpopulationlist.get(position).getRank()));
           // ...likewise pass all other data ...

           mContext.startActivity(intent);

        }
    });

    return view;
}

// Filter Class
public void filter(String charText) {
    charText = charText.toLowerCase(Locale.getDefault());
    worldpopulationlist.clear();
    if (charText.length() == 0) {
        worldpopulationlist.addAll(arraylist);
    } else {
        for (WorldPopulation wp : arraylist) {
            if (wp.getCountry().toLowerCase(Locale.getDefault())
                    .contains(charText) ) {
                worldpopulationlist.add(wp);
            }
            if(wp.getRank().toLowerCase(Locale.getDefault())
                    .contains(charText)) {
                worldpopulationlist.add(wp);
            }
            if (wp.getPopulation().toLowerCase(Locale.getDefault())
                    .contains(charText)) {
                worldpopulationlist.add(wp);
            }
        }
    }
    notifyDataSetChanged();
}

}

Answer 1

为了在 onCLick() 方法中获取项目的 "old" 位置，请使用

arraylist.indexOf( getItem(position) )

像这样更改您的过滤方法以避免多次添加相同的项目：

// Filter Class
public void filter(String charText) {
charText = charText.toLowerCase(Locale.getDefault());
worldpopulationlist.clear();
if (charText.length() == 0) {
    worldpopulationlist.addAll(arraylist);
} 
else {
    boolean addToList;

    for (WorldPopulation wp : arraylist) {
        addToList = false;

        if (wp.getCountry().toLowerCase(Locale.getDefault())
                 .contains(charText) ) {
            addToList = true;
        }
        if(wp.getRank().toLowerCase(Locale.getDefault())
                  .contains(charText)) {
            addToList = true;
        }
        if (wp.getPopulation().toLowerCase(Locale.getDefault())
                   .contains(charText)) {
            addToList = true;
        }

        // now add the item to your list if it matches the search criteria
        if (addToList) {                      
            worldpopulationlist.add(wp);
        }

    }
    notifyDataSetChanged();
}

}

带有搜索过滤器的列表视图适配器 class 在搜索时未发送准确位置

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