在 Spark 中嵌套 JSON

Question

我将以下 JSON 作为 DataFrame 加载：

root
 |-- data: struct (nullable = true)
 |    |-- field1: string (nullable = true)
 |    |-- field2: string (nullable = true)
 |-- moreData: array (nullable = true)
 |    |-- element: struct (containsNull = true)
 |    |    |-- more1: string (nullable = true)
 |    |    |-- more2: string (nullable = true)
 |    |    |-- more3: string (nullable = true)

我想从此 DataFrame 中获取以下 RDD：

RDD[(more1, more2, more3, field1, field2)]

我该怎么做？我想我必须对嵌套的 JSON?

使用 flatMap

Answer 1

explode 和点语法的组合应该可以解决问题：

import org.apache.spark.sql.functions.explode

case class Data(field1: String, field2: String)
case class MoreData(more1: String, more2: String, more3: String)

val df = sc.parallelize(Seq(
  (Data("foo", "bar"), Array(MoreData("a", "b", "c"), MoreData("d", "e", "f")))
)).toDF("data", "moreData")

df.printSchema
// root
//  |-- data: struct (nullable = true)
//  |    |-- field1: string (nullable = true)
//  |    |-- field2: string (nullable = true)
//  |-- moreData: array (nullable = true)
//  |    |-- element: struct (containsNull = true)
//  |    |    |-- more1: string (nullable = true)
//  |    |    |-- more2: string (nullable = true)
//  |    |    |-- more3: string (nullable = true)

val columns = Seq(
  $"moreData.more1", $"moreData.more2", $"moreData.more3",
  $"data.field1", $"data.field2")

val aRDD = df.withColumn("moreData", explode($"moreData"))
  .select(columns: _*)
  .rdd

aRDD.collect
// Array[org.apache.spark.sql.Row] = Array([a,b,c,foo,bar], [d,e,f,foo,bar])

根据您的要求，您可以使用 map 从行中提取值：

import org.apache.spark.sql.Row

aRDD.map{case Row(m1: String, m2: String, m3: String, f1: String, f2: String) =>
  (m1, m2, m3, f1, f2)}

另见

在 Spark 中嵌套 JSON

Nested JSON in Spark

scala

dataframe

apache-spark

apache-spark-sql