Python：去掉字符串开头的数字

Question

我有一些这样的字符串：

string1 = "123.123.This is a string some other numbers"
string2 = "1. This is a string some numbers"
string3 = "12-3-12.This is a string 123"
string4 = "123-12This is a string 1234"

我需要从字符串的开头删除这些数字。我尝试了 strip[start: end] 方法，但由于字符串格式不规则，我无法使用它？有什么建议么？

Answer 1

您可以使用 str.lstrip():

从开头删除所有数字、点、破折号和空格

string1.lstrip('0123456789.- ')

str.strip() 的参数被视为集合，例如字符串开头属于该集合的任何字符都将被删除，直到字符串不再以此类字符开头。

演示：

>>> samples = """\
... 123.123.This is a string some other numbers
... 1. This is a string some numbers
... 12-3-12.This is a string 123
... 123-12This is a string 1234
... """.splitlines()
>>> for sample in samples:
...     print 'From: {!r}\nTo:   {!r}\n'.format(
...         sample, sample.lstrip('0123456789.- '))
...
From: '123.123.This is a string some other numbers'
To:   'This is a string some other numbers'

From: '1. This is a string some numbers'
To:   'This is a string some numbers'

From: '12-3-12.This is a string 123'
To:   'This is a string 123'

From: '123-12This is a string 1234'
To:   'This is a string 1234'

Answer 2

这与@MartijnPieters 的回答几乎相同，但如果要在数字顶部删除大量标点符号和空白字符，我们可以使用 string 模块中的常量：

import string
nonalpha = string.digits + string.punctuation + string.whitespace
out = some_string.lstrip(nonalpha)

所以对于给定的样本：

for sample in [string1, string2, string3, string4]:
    print('From: {!r}\nTo:   {!r}\n'.format(sample, sample.lstrip(nonalpha)))

输出：

From: '123.123.This is a string some other numbers'
To:   'This is a string some other numbers'

From: '1. This is a string some numbers'
To:   'This is a string some numbers'

From: '12-3-12.This is a string 123'
To:   'This is a string 123'

From: '123-12This is a string 1234'
To:   'This is a string 1234'

Python：去掉字符串开头的数字

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