使用 Linq.js 对 JSON 数据的多个字段进行 SUM 和 GROUP BY
SUM and GROUP BY on multiple fields of JSON data using Linq.js
我有一个 JSON 数据,我需要对数据进行分组和求和。假设我有一个 json 对象,它看起来像这样:
var dataString='[{"Company":"ABC","Focus":"Operate","Completed":"50","Remaining":"25"},{"Company":"ABC","Focus":"Operate","Completed":"20","Remaining":"50"},{"Company":"DEF","Focus":"Optimize","Completed":"100","Remaining":"75"},{"Company":"XYZ","Focus":"Innovate","Completed":"100","Remaining":"75"},{"Company":"ABC","Focus":"Improve","Completed":"50","Remaining":"50"},{"Company":"ABC","Focus":"Optimize","Completed":"50","Remaining":"25"},{"Company":"DEF","Focus":"Operate","Completed":"50","Remaining":"25"},{"Company":"ABC","Focus":"Improve","Completed":"50","Remaining":"25"},{"Company":"XYZ","Focus":"Operate","Completed":"50","Remaining":"25"},{"Company":"XYZ","Focus":"Operate","Completed":"50","Remaining":"25"},{"Company":"XYZ","Focus":"Optimize","Completed":"20","Remaining":"50"}]';
output :: Array inside an array,第一个数组应该包含 company 和另一个数组,它将包含我的焦点区域已完成和剩余数据的总和。
Company:
1. ABC --Focus -- 1.Operate -- Completed :70 ,Remaining:75
2.Improve -- Completed:100 ,Remaining:75
3.Optimize -- Completed:50 ,Remaining:25
2. DEF--Focus-- 1.Operate -- Completed:50 ,Remaining:25
2.Optimize -- Completed:100 ,Remaining:75
3. XYZ--Focus-- 1.Innovate -- Completed:100 ,Remaining:75
2.Operate -- Completed:100 ,Remaining:50
3.Optimize -- Completed:20 ,Remaining:50
我已尝试通过以下查询来实现此目的:
var resultxyz = Enumerable.From(dataString).GroupBy("$.Company", null,
function (key, g) {
var resultxyz = {
z: key,
totalCompleted: g.Sum("$.Completed"),
totalRemaining: g.Sum("$.Remaining")
}
return resultxyz ;
}).ToArray();
但这只是对公司进行分组,我也必须关注焦点。
任何想法或建议都会有很大帮助。
基本上您正在寻找一个两层分组。首先对所有公司进行整体分组,然后在每个组内对焦点进行分组。有许多不同的方法可以对此进行建模,但最直接的方法是:
var query = Enumerable.From(data)
.GroupBy("$.Company", null,
function (key, g) {
return {
Company: key,
Result: Enumerable.From(g)
.GroupBy("$.Focus", null,
"{ Focus: $, Completed: $$.Sum('Number($.Completed)'), Remaining: $$.Sum('Number($.Remaining)') }"
)
.ToArray()
};
}
)
.ToArray();
注意Number()
函数的使用。由于 Completed
和 Remaining
属性是字符串,因此求和不会像预期的那样有效。我们需要事先将它们转换为数字。
我有一个 JSON 数据,我需要对数据进行分组和求和。假设我有一个 json 对象,它看起来像这样:
var dataString='[{"Company":"ABC","Focus":"Operate","Completed":"50","Remaining":"25"},{"Company":"ABC","Focus":"Operate","Completed":"20","Remaining":"50"},{"Company":"DEF","Focus":"Optimize","Completed":"100","Remaining":"75"},{"Company":"XYZ","Focus":"Innovate","Completed":"100","Remaining":"75"},{"Company":"ABC","Focus":"Improve","Completed":"50","Remaining":"50"},{"Company":"ABC","Focus":"Optimize","Completed":"50","Remaining":"25"},{"Company":"DEF","Focus":"Operate","Completed":"50","Remaining":"25"},{"Company":"ABC","Focus":"Improve","Completed":"50","Remaining":"25"},{"Company":"XYZ","Focus":"Operate","Completed":"50","Remaining":"25"},{"Company":"XYZ","Focus":"Operate","Completed":"50","Remaining":"25"},{"Company":"XYZ","Focus":"Optimize","Completed":"20","Remaining":"50"}]';
output :: Array inside an array,第一个数组应该包含 company 和另一个数组,它将包含我的焦点区域已完成和剩余数据的总和。
Company:
1. ABC --Focus -- 1.Operate -- Completed :70 ,Remaining:75
2.Improve -- Completed:100 ,Remaining:75
3.Optimize -- Completed:50 ,Remaining:25
2. DEF--Focus-- 1.Operate -- Completed:50 ,Remaining:25
2.Optimize -- Completed:100 ,Remaining:75
3. XYZ--Focus-- 1.Innovate -- Completed:100 ,Remaining:75
2.Operate -- Completed:100 ,Remaining:50
3.Optimize -- Completed:20 ,Remaining:50
我已尝试通过以下查询来实现此目的:
var resultxyz = Enumerable.From(dataString).GroupBy("$.Company", null,
function (key, g) {
var resultxyz = {
z: key,
totalCompleted: g.Sum("$.Completed"),
totalRemaining: g.Sum("$.Remaining")
}
return resultxyz ;
}).ToArray();
但这只是对公司进行分组,我也必须关注焦点。 任何想法或建议都会有很大帮助。
基本上您正在寻找一个两层分组。首先对所有公司进行整体分组,然后在每个组内对焦点进行分组。有许多不同的方法可以对此进行建模,但最直接的方法是:
var query = Enumerable.From(data)
.GroupBy("$.Company", null,
function (key, g) {
return {
Company: key,
Result: Enumerable.From(g)
.GroupBy("$.Focus", null,
"{ Focus: $, Completed: $$.Sum('Number($.Completed)'), Remaining: $$.Sum('Number($.Remaining)') }"
)
.ToArray()
};
}
)
.ToArray();
注意Number()
函数的使用。由于 Completed
和 Remaining
属性是字符串,因此求和不会像预期的那样有效。我们需要事先将它们转换为数字。