如何使用scala Elem 生成球衣text/xml?

How to use scala Elem produces jersey text/xml?

我已经写了一个通用的方法来通过scala.xml lib生成Elem类型。但是 Jersey 使用 JAXB,意味着将 xml 信息与 Java 对象绑定。我怎么能简单地使用 scala 的 Elem 类型来避免构造对象呢?

简单代码为:

  @GET  
  @Path("sitemap.xml")  
  @Produces(Array(MediaType.APPLICATION_XML))  
  def sitemap( @Context client: DaoService[Future]) = {  
    val x: Elem = Common.defaultXml()  
    x  
  } 

您将需要一个自定义 MessageBodyWriter to handle the Elem type. This component is what all Java object go through to serialize to the response stream. You can read more at JAX-RS Entity Providers。例如对于 Elem 你可以使用类似

import java.io.OutputStream
import java.lang.Class
import java.lang.reflect.Type
import java.lang.annotation.Annotation

import javax.ws.rs.{ Produces }
import javax.ws.rs.core.{ MultivaluedMap, MediaType }
import javax.ws.rs.ext.{ MessageBodyWriter, Provider }

import scala.xml.Elem

@Provider
@Produces(Array("application/xml"))
class ElemWriterProvider extends MessageBodyWriter[Elem] {

  override def isWriteable(cls: Class[_], genericType: Type,
                           annotations: Array[Annotation],
                           mediaType: MediaType) = {
    classOf[Elem].isAssignableFrom(cls)
  }

  override def getSize(elem: Elem, cls: Class[_], genericType: Type,
                       annotations: Array[Annotation], mediaType: MediaType) = {
    -1L
  }

  override def writeTo(elem: Elem, cls: Class[_], genericType: Type,
                       annotations: Array[Annotation], mediaType: MediaType,
                       headers: MultivaluedMap[String, Object],
                       entityStream: OutputStream): Unit = {
    println("------- writeTo --------")
    entityStream.write(elem.buildString(false).getBytes)
  }
}

那你要么显式注册写手,要么让扫码获取。


更新

另一个选项(不需要自定义提供程序)是简单地 return XML 字符串 ;-)