PHP 关联数组：独特的函数值

Question

所以由于一些讨厌的框架问题，我有点卡在这里。基本上，我从用户输入中获取一个字符串，并将其替换为我的模型中仅在调用时已知的值。

我的结构是这样的：

static public $placeholders = array("[REPLACE_STRING_1]"=>'firstName',
                                    "[REPLACE_STRING_2]"=>'DateTime->format(\'aa,bb\')');
//Problem line above.  Very messy, format is an arm long and painful

public function myfunction(ModelClass $master) {
    $body = $this->sampleService->get('samplebody'); // populate body from DB
    foreach(static::$placeholders as $key => $value){
        $body = str_replace($key, $master->value, $body);
    }
    return $body;
}

所以这会产生一些非常难看的代码。我的老板想编辑它，使一个函数成为数组的一部分，分配给每个条目，这将运行 filter/edit 代码。像

function dateFormat($prop){
    return $prop->format('aa,bb');
}
function asIs($prop){
    return $prop;
}

static public $placeholders = array("[REPLACE_STRING_1]"=>['firstName', asIs]
                                    "[REPLACE_STRING_2]"=>['DateTime', dateFormat]);

PHP 中是否有任何现有的结构或函数使这成为可能，或者他的代码愿望只是一个白日梦？

编辑：我找到了一个与下面发布的答案非常相似的解决方案，但需要进行一些必要的修改才能传递变量。

function dateFormat ($prop, $master) {
    return $master->$prop->format('aabb');
}
function asIs ($prop, $master) {
    return $appointment->$prop;
}
static public $placeholders = array("[REPLACE_STRING_1]"=>['firstname','asIs'], 
                                    "[REPLACE_STRING_2]"=>['DateTime', dateFormat];

//instatiate service to get sampleService values

//main difference here
public function buildBody(ModelClass $master) {
    $body = $this->sampleService->get('samplebody');
    foreach(static::$placeholders as $key => $value){
        $body = preg_replace_callback('/'.preg_quote($key).'/',
        //Use closure here to pass in $master, otherwise laravel gets angry about strings instead of objects
        function ($matches) use ($master) {
            $placeholder = static::placeholders[$matches[0]];
            $func = $placeholder[1];
            $prop = $placeholder[0];
            return call_user_func(array($this, $func), $prop, $appointment);
        }, $body);
    }
    return $body;
}

总而言之，这对我来说是一个非常有趣的问题，我正试图找到一种方法来进一步清理它。将您的答案标记为正确，因为它极大地帮助了我们。

Answer 1

如果我答对了问题，我会选择 preg_replace_callback 并像这样做：

function dateFormat($prop){
    return $prop;
}

function asIs($prop){
    return $prop;
}

static public $placeholders = array(
    "[REPLACE_STRING_1]"=>['firstName', 'asIs'],
    "[REPLACE_STRING_2]"=>['DateTime', 'dateFormat']
);

private function replace($matches) {
    $placeholder = static::$placeholders[$matches[0]];
    $func = $placeholder[1];
    $prop = $placeholder[0];

    // this calls your class methods ('asIs', 'dateFormat')
    // with $prop = 'firstName' etc.
    return call_user_func(array($this, $func), $prop);
}

public function myfunction(ModelClass $master) {
    $body = $this->sampleService->get('samplebody');

    foreach(static::$placeholders as $key => $value) {
        // use a callback replace method instead of str_replace
        $body = preg_replace_callback('/' . preg_quote($key) . '/', array($this, 'replace'), $body);
    }

    return $body;
}

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