如何编写数据触发器以通过在 WPF 中单击动态按钮打开弹出窗口？

Question

我的 WPF 应用程序中有一个动态按钮，单击任何一个按钮时，弹出窗口应打开，相应的按钮应将背景颜色变为橙色，按钮的其余部分应为默认背景颜色使用 DataTrigger 和另一个条件，在弹出窗口关闭时，相应的按钮背景颜色应变为默认颜色。

Note: I Can't able to give Name for the Buttons because of Dynamic Creation. Here I placed 5 Buttons without Name Property, Consider the Button as Dynamic Creation

我的XAML源代码是

<Grid>
    <Grid Height="30px" VerticalAlignment="Top" Margin="0,50,0,0">
        <Grid.ColumnDefinitions>
            <ColumnDefinition Width="100px"/>
            <ColumnDefinition Width="100px"/>
            <ColumnDefinition Width="100px"/>
            <ColumnDefinition Width="100px"/>
            <ColumnDefinition Width="100px"/>
        </Grid.ColumnDefinitions>
        <Button Content="One" Grid.Column="0" HorizontalAlignment="Center" VerticalAlignment="Center" Width="75"/>
        <Button Content="Two" Grid.Column="1" HorizontalAlignment="Center" VerticalAlignment="Center" Width="75"/>
        <Button Content="Three" Grid.Column="2" HorizontalAlignment="Center" VerticalAlignment="Center" Width="75"/>
        <Button Content="Four" Grid.Column="3" HorizontalAlignment="Center" VerticalAlignment="Center" Width="75"/>
        <Button Content="Five" Grid.Column="4" HorizontalAlignment="Center" VerticalAlignment="Center" Width="75"/>
    </Grid>
    <Grid>
        <Popup Name="sPop" Placement="Mouse" StaysOpen="False">
            <Grid>
                <TextBlock HorizontalAlignment="Center" VerticalAlignment="Center" TextWrapping="Wrap" Text="Welcome to Popup Screen"/>
            </Grid>
        </Popup>
    </Grid>
</Grid>

Answer 1

我试图在不使用 DataTrigger 的情况下实现您的要求。这是用于更改背景的简单样式触发器：

<Style TargetType="Button">
    <Style.Triggers>
        <Trigger Property="Button.IsFocused" Value="True">
            <Setter Property="Button.Background" Value="Red" />
        </Trigger>
    </Style.Triggers>
</Style>

您的每个按钮都可以处理 Click 事件：

<Button Content="One" Grid.Column="0" HorizontalAlignment="Center" VerticalAlignment="Center" Width="75" Click="Button_Click" />
...

我们需要以某种方式处理您的 Popup。我刚刚命名它：

<Popup Name="popup" Placement="Mouse" StaysOpen="False">
...

点击事件很简单：

private void Button_Click(object sender, RoutedEventArgs e) {
    var button = sender as Button;
    if (popup.IsOpen) { popup.IsOpen = false; }
    popup.PlacementTarget = button;
    popup.IsOpen = true;
}

所以它会如您所愿。

Answer 2

您不能使用 DataTriggers 执行此操作。 DataTriggers 适用于 Data-Based 场景，因此如果您使用 DataBinding，则使用它们。

推荐方法：

为您的弹出窗口指定一个名称。并使用行为。

<Button ...>
    <Button.Style>
        <Style TargetType="Button">
            <Style.Triggers>
                <Trigger Property="IsFocused" Value="True">
                    <Setter Property="Background" Value="Red"/>
                </Trigger>
            </Style.Triggers>
        </Style>
    </Button.Style>
    <i:Interaction.Triggers>
        <i:EventTrigger EventName="Click">
            <i:Interaction.Behaviors>
                <ei:ConditionBehavior>
                    <ei:ConditionalExpression>
                        <ei:ComparisonCondition LeftOperand="{Binding IsFocused, RelativeSource={RelativeSource Mode=FindAncestor, AncestorType=Button}}" RightOperand="True"/>
                    </ei:ConditionalExpression>
                </ei:ConditionBehavior>
            </i:Interaction.Behaviors>
            <ei:ChangePropertyAction TargetObject="{Binding ElementName=Popup1}" PropertyName="IsOpen" Value="True"/>
        </i:EventTrigger>
    </i:Interaction.Triggers>
</Button>

要使用 Blend 程序集：

添加对 System.Windows.Interactivity 和 Microsoft.Expression.Interactions 以及以下命名空间的引用：

xmlns:i="http://schemas.microsoft.com/expression/2010/interactivity" 
xmlns:ei="http://schemas.microsoft.com/expression/2010/interactions"

还原源按钮的旧背景：

<Button>
    <i:Interaction.Triggers>
        <i:EventTrigger EventName="Click">
            <i:Interaction.Behaviors>
                <ei:ConditionBehavior>
                    <ei:ConditionalExpression>
                        <ei:ComparisonCondition LeftOperand="{Binding IsFocused, RelativeSource={RelativeSource Mode=FindAncestor, AncestorType=Button}}" RightOperand="True"/>
                    </ei:ConditionalExpression>
                </ei:ConditionBehavior>
            </i:Interaction.Behaviors>

            <!-- Store Button's old Background -->
            <ei:ChangePropertyAction TargetObject="{Binding ElementName=Popup1}" PropertyName="Tag" Value="{Binding Background, RelativeSource={RelativeSource Mode=FindAncestor, AncestorType=Button}}"/>

            <!-- Change Button's Background -->
            <ei:ChangePropertyAction PropertyName="Background" Value="Purple"/>

            <!-- Open Popup -->
            <ei:ChangePropertyAction TargetObject="{Binding ElementName=Popup1}" PropertyName="IsOpen" Value="True"/>

            <!-- Save this Button, Popup will use it to revert back its old Background -->
            <ei:ChangePropertyAction TargetObject="{Binding ElementName=Popup1}" PropertyName="PlacementTarget" Value="{Binding RelativeSource={RelativeSource Mode=FindAncestor, AncestorType=Button}}"/>

        </i:EventTrigger>
    </i:Interaction.Triggers>
</Button>

<Popup x:Name="Popup1" Placement="Mouse" StaysOpen="False">
    <i:Interaction.Triggers>
        <i:EventTrigger EventName="Closed">
            <ei:ChangePropertyAction 
                        TargetObject="{Binding PlacementTarget, RelativeSource={RelativeSource Mode=FindAncestor, AncestorType=Popup}}" 
                        PropertyName="Background" 
                        Value="{Binding Tag, RelativeSource={RelativeSource Mode=FindAncestor, AncestorType=Popup}}" />
        </i:EventTrigger>
    </i:Interaction.Triggers>
    <Grid>
        <TextBlock HorizontalAlignment="Center" VerticalAlignment="Center" TextWrapping="Wrap" Text="Welcome to Popup Screen"/>
    </Grid>
</Popup>

如何编写数据触发器以通过在 WPF 中单击动态按钮打开弹出窗口？

How to Write a Data Trigger to open Popup by Clicking dynamic Button in WPF?

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