AngularJS 带有 `$q` 的执行顺序 -- Chaining Promises

AngularJS execution order with `$q` -- Chaining Promises

以下方法有效:

$q.when()
        .then(checkCookieToken)         // check if cookie already exists e.g. in cookie
        .then(setHeader)                // set Header with REST-Token e.g from cookie
        .then(checkTokenOnline)         // if not OK logout
        .then(getMenu)                  // if previous OK get navigation menu
        .then(getDataResource)          // set ngResource
        .then(getData);                 // and query it

4 个问题:

1) 如果例如checkTokenOnline不行,我不想执行其余的功能,我怎么能在这个时候退出(exit,break,whatever,..)?

2) 如何设置一些并联一些串行?

3) 如何在它们之间传输数据?

4) 如何使以下函数依赖于其先前的结果?

你问的是如何在 promises 中函数。

3) How can I transfer data between them?

4) How can I make the following function depend on its previous result?

Return 链中下一个函数的数据(或承诺):

var p2 = p1.then ( function (data) {
     var nextData = someFn(data);
     return nextData;
});

var p3 = p2.then ( function (nextData) {
     var nextData2 = someOtherFn(nextData);
     return nextData2;
});

//return for further chaining
return p3;

1) If e.g. checkTokenOnline is not OK, I don't want to execute the rest functions, how can I quit (exit, break, whatever,..) at this point?

为了拒绝一个承诺,让你的函数抛出一个错误。该链将跳过所有 .then 方法,直到您提供错误处理程序。

var p2 = p1.then ( function checkTokenOnline (response) {
             if ( isBadFn(response) {
                 throw error;
             } else {
                 return nextData;
             }
   }) .then ( someFn 
    ) .then ( someOtherFn
    ) .catch ( function (error) {
          // someFn and someOtherFn skipped
          //log error
          throw error;
   });

 //return for further chaining
 return p2;

2) How can I set some of them parallel and some of them serial ?

要并行执行两个函数 运行,请做出两个承诺。使用 $q.all 等待它们都完成。

var p1 = $q.when ( fn1() );
var p2 = $q.when ( fn2() );

var p3 = $q.all ( [p1, p2] );

var p4 = p3.then ( function (responseList) {
      var response1 = responseList[0];
      var response2 = responseList[1];
      return something;
}). catch ( function (error) {
      //log error
      throw error;
});

//return for further chaining
return p4;

请注意 $q.all 并不 有弹性 。如果任何 promise 抛出错误,.then 方法将被跳过,只有第一个错误会转到 .catch 方法。

函数式编程的经验法则是总是return一些


有用的链接