MSSQL - 2 个包含多行的表合并为一个 table
MSSQL - 2 Tables with multiple rows merge in one table
我有 2 个选择 returns 2 table，每个 table 我有 12 行和 2 列，现在我只想有一个 table.
---- First Table
select f. date as Date, f.value as Month1
from
(
select b.date as date, sum(b.value) as value
from business bu
join bus_cat buc on buc.id = bu.id
join cat ct on ct.id = buc.type_id
join bus2 b on b.id = buc.id
where ct.id = 1
and b.value <> 0
and b.date between @start and @actual
and bu.name = @bu_name
group by b.date, b.value
union all
select b5.date as date, sum(b5.value) as value
from bus bu
join bus_cat buc on buc.id = bu.id
join cat ct on ct.id = buc.type_id
join bus3 b5 on b5.id = buc.id
where ct.id = 1
and b5.value <> 0
and b5.date between @nextM and @endM
and bu.name = @bu_name
group by b5.date, b5.value
) as f
---- Second Table
select f1. date as Date, f1.value as Month2
from
(
select b.date as date, sum(b.value) as value
from business bu
join bus_cat buc on buc.id = bu.id
join cat ct on ct.id = buc.type_id
join bus2 b on b.id = buc.id
where ct.id = 1
and b.value <> 0
and b.date between @start and @actual
and bu.name = @bu_name
group by b.date, b.value
union all
select b5.date as date, sum(b5.value) as value
from bus bu
join bus_cat buc on buc.id = bu.id
join cat ct on ct.id = buc.type_id
join bus3 b5 on b5.id = buc.id
where ct.id = 1
and b5.value <> 0
and b5.date between @nextM and @endM
and bu.name = @bu_name
group by b5.date, b5.value
) as f1
第一个 table 的实际输出是：
Date Month1
2015-01-01 23
2015-01-01 77
第二个：
Date Month2
2015-01-01 88
2015-01-01 90
我只想合并这 2 table 看起来像
Date Month1 Date Month2
2015-01-01 23 2015-01-01 77
2015-01-01 28 2015-01-01 787
正如我在评论中所说，一个简单的连接就可以解决问题。类似于：
SELECT *
FROM
(
select b.date as date, sum(b.value) as value
from business bu
join bus_cat buc on buc.id = bu.id
join cat ct on ct.id = buc.type_id
join bus2 b on b.id = buc.id
where ct.id = 1
and b.value <> 0
and b.date between @start and @actual
and bu.name = @bu_name
group by b.date, b.value
union all
select b5.date as date, sum(b5.value) as value
from bus bu
join bus_cat buc on buc.id = bu.id
join cat ct on ct.id = buc.type_id
join bus3 b5 on b5.id = buc.id
where ct.id = 1
and b5.value <> 0
and b5.date between @nextM and @endM
and bu.name = @bu_name
group by b5.date, b5.value
) as f
LEFT JOIN (
select b.date as date, sum(b.value) as value
from business bu
join bus_cat buc on buc.id = bu.id
join cat ct on ct.id = buc.type_id
join bus2 b on b.id = buc.id
where ct.id = 1
and b.value <> 0
and b.date between @start and @actual
and bu.name = @bu_name
group by b.date, b.value
union all
select b5.date as date, sum(b5.value) as value
from bus bu
join bus_cat buc on buc.id = bu.id
join cat ct on ct.id = buc.type_id
join bus3 b5 on b5.id = buc.id
where ct.id = 1
and b5.value <> 0
and b5.date between @nextM and @endM
and bu.name = @bu_name
group by b5.date, b5.value
) as f1
ON f.date = f1.date
编辑
顺便说一句，这个查询可以简化，看起来查询中有很多相似之处。
我有 2 个选择 returns 2 table，每个 table 我有 12 行和 2 列，现在我只想有一个 table.
---- First Table
select f. date as Date, f.value as Month1
from
(
select b.date as date, sum(b.value) as value
from business bu
join bus_cat buc on buc.id = bu.id
join cat ct on ct.id = buc.type_id
join bus2 b on b.id = buc.id
where ct.id = 1
and b.value <> 0
and b.date between @start and @actual
and bu.name = @bu_name
group by b.date, b.value
union all
select b5.date as date, sum(b5.value) as value
from bus bu
join bus_cat buc on buc.id = bu.id
join cat ct on ct.id = buc.type_id
join bus3 b5 on b5.id = buc.id
where ct.id = 1
and b5.value <> 0
and b5.date between @nextM and @endM
and bu.name = @bu_name
group by b5.date, b5.value
) as f
---- Second Table
select f1. date as Date, f1.value as Month2
from
(
select b.date as date, sum(b.value) as value
from business bu
join bus_cat buc on buc.id = bu.id
join cat ct on ct.id = buc.type_id
join bus2 b on b.id = buc.id
where ct.id = 1
and b.value <> 0
and b.date between @start and @actual
and bu.name = @bu_name
group by b.date, b.value
union all
select b5.date as date, sum(b5.value) as value
from bus bu
join bus_cat buc on buc.id = bu.id
join cat ct on ct.id = buc.type_id
join bus3 b5 on b5.id = buc.id
where ct.id = 1
and b5.value <> 0
and b5.date between @nextM and @endM
and bu.name = @bu_name
group by b5.date, b5.value
) as f1
第一个 table 的实际输出是：
Date Month1
2015-01-01 23
2015-01-01 77
第二个：
Date Month2
2015-01-01 88
2015-01-01 90
我只想合并这 2 table 看起来像
Date Month1 Date Month2
2015-01-01 23 2015-01-01 77
2015-01-01 28 2015-01-01 787
正如我在评论中所说，一个简单的连接就可以解决问题。类似于：
SELECT *
FROM
(
select b.date as date, sum(b.value) as value
from business bu
join bus_cat buc on buc.id = bu.id
join cat ct on ct.id = buc.type_id
join bus2 b on b.id = buc.id
where ct.id = 1
and b.value <> 0
and b.date between @start and @actual
and bu.name = @bu_name
group by b.date, b.value
union all
select b5.date as date, sum(b5.value) as value
from bus bu
join bus_cat buc on buc.id = bu.id
join cat ct on ct.id = buc.type_id
join bus3 b5 on b5.id = buc.id
where ct.id = 1
and b5.value <> 0
and b5.date between @nextM and @endM
and bu.name = @bu_name
group by b5.date, b5.value
) as f
LEFT JOIN (
select b.date as date, sum(b.value) as value
from business bu
join bus_cat buc on buc.id = bu.id
join cat ct on ct.id = buc.type_id
join bus2 b on b.id = buc.id
where ct.id = 1
and b.value <> 0
and b.date between @start and @actual
and bu.name = @bu_name
group by b.date, b.value
union all
select b5.date as date, sum(b5.value) as value
from bus bu
join bus_cat buc on buc.id = bu.id
join cat ct on ct.id = buc.type_id
join bus3 b5 on b5.id = buc.id
where ct.id = 1
and b5.value <> 0
and b5.date between @nextM and @endM
and bu.name = @bu_name
group by b5.date, b5.value
) as f1
ON f.date = f1.date
编辑
顺便说一句，这个查询可以简化，看起来查询中有很多相似之处。