如何创建波路径 Swift

Question

我希望我的节点以正弦曲线波行进，我尝试将其用于 CGPath。如何创建遵循正弦曲线的 CGPath？除了手动找到曲线上的点，还有什么办法吗？或者我可以只传递一个正弦函数吗？

let action = SKAction.followPath(<the sine path>, asOffset: true, orientToPath: true, duration: 5)

这可以通过贝塞尔路径完成然后转换为 CGPaths 吗？谢谢

Answer 1

不，没有从函数构建路径的内置方法，但您可以轻松编写自己的方法。在 Swift 3:

/// Build path within rectangle
///
/// Given a `function` that converts values between zero and one to another values between zero and one, this method will create `UIBezierPath` within `rect` using that `function`.
///
/// - parameter rect:      The `CGRect` of points on the screen.
///
/// - parameter count:     How many points should be rendered. Defaults to `rect.size.width`.
///
/// - parameter function:  A closure that will be passed an floating point number between zero and one and should return a return value between zero and one as well.

private func path(in rect: CGRect, count: Int? = nil, function: (CGFloat) -> (CGFloat)) -> UIBezierPath {
    let numberOfPoints = count ?? Int(rect.size.width)

    let path = UIBezierPath()
    path.move(to: convert(point: CGPoint(x: 0, y: function(0)), in: rect))
    for i in 1 ..< numberOfPoints {
        let x = CGFloat(i) / CGFloat(numberOfPoints - 1)
        path.addLine(to: convert(point: CGPoint(x: x, y: function(x)), in: rect))
    }
    return path
}

/// Convert point with x and y values between 0 and 1 within the `CGRect`.
///
/// - parameter point:  A `CGPoint` value with x and y values between 0 and 1.
/// - parameter rect:   The `CGRect` within which that point should be converted.

private func convert(point: CGPoint, in rect: CGRect) -> CGPoint {
    return CGPoint(
        x: rect.origin.x + point.x * rect.size.width,
        y: rect.origin.y + rect.size.height - point.y * rect.size.height
    )
}

因此，让我们传递一个函数，该函数在跨越 rect 的 width 时执行一条正弦曲线：

func sinePath(in rect: CGRect, count: Int? = nil) -> UIBezierPath {
    // note, since sine returns values between -1 and 1, let's add 1 and divide by two to get it between 0 and 1
    return path(in: rect, count: count) { (sin([=11=] * .pi * 2.0) + 1.0) / 2.0 }
}

注意，上面假设你想从左到右遍历，构建函数定义的路径。您还可以做更多的参数化再现：

/// Build path within rectangle
///
/// Given a `function` that converts values between zero and one to another values between zero and one, this method will create `UIBezierPath` within `rect` using that `function`.
///
/// - parameter rect:      The `CGRect` of points on the screen.
///
/// - parameter count:     How many points should be rendered. Defaults to `rect.size.width` or `rect.size.width`, whichever is larger.
///
/// - parameter function:  A closure that will be passed an floating point number between zero and one and should return a `CGPoint` with `x` and `y` values between 0 and 1.

private func parametricPath(in rect: CGRect, count: Int? = nil, function: (CGFloat) -> (CGPoint)) -> UIBezierPath {
    let numberOfPoints = count ?? max(Int(rect.size.width), Int(rect.size.height))

    let path = UIBezierPath()
    let result = function(0)
    path.move(to: convert(point: CGPoint(x: result.x, y: result.y), in: rect))
    for i in 1 ..< numberOfPoints {
        let t = CGFloat(i) / CGFloat(numberOfPoints - 1)
        let result = function(t)
        path.addLine(to: convert(point: CGPoint(x: result.x, y: result.y), in: rect))
    }
    return path
}

然后可以用正弦曲线修改x坐标，增加y:

func verticalSinePath(in rect: CGRect, count: Int? = nil) -> UIBezierPath {
    // note, since sine returns values between -1 and 1, let's add 1 and divide by two to get it between 0 and 1
    return parametricPath(in: rect, count: count) { CGPoint(
        x: (sin([=13=] * .pi * 2.0) + 1.0) / 2.0,
        y: [=13=]
    ) }
}

这样做的优点是您现在还可以定义您想要的任何类型的路径，例如一个螺旋：

func spiralPath(in rect: CGRect, count: Int? = nil) -> UIBezierPath {
    return parametricPath(in: rect, count: count) { t in
        let r = 1.0 - sin(t * .pi / 2.0)
        return CGPoint(
            x: (r * sin(t * 10.0 * .pi * 2.0) + 1.0) / 2.0,
            y: (r * cos(t * 10.0 * .pi * 2.0) + 1.0) / 2.0
        )
    }
}

以下是上述内容的 Swift 2 个版本：

/// Build path within rectangle
///
/// Given a `function` that converts values between zero and one to another values between zero and one, this method will create `UIBezierPath` within `rect` using that `function`.
///
/// - parameter rect:      The `CGRect` of points on the screen.
///
/// - parameter count:     How many points should be rendered. Defaults to `rect.size.width`.
///
/// - parameter function:  A closure that will be passed an floating point number between zero and one and should return a return value between zero and one as well.

private func path(in rect: CGRect, count: Int? = nil, function: (CGFloat) -> (CGFloat)) -> UIBezierPath {
    let numberOfPoints = count ?? Int(rect.size.width)

    let path = UIBezierPath()
    path.moveToPoint(convert(point: CGPoint(x: 0, y: function(0)), rect: rect))
    for i in 1 ..< numberOfPoints {
        let x = CGFloat(i) / CGFloat(numberOfPoints - 1)
        path.addLineToPoint(convert(point: CGPoint(x: x, y: function(x)), rect: rect))
    }
    return path
}

/// Convert point with x and y values between 0 and 1 within the `CGRect`.
///
/// - parameter point:  A `CGPoint` value with x and y values between 0 and 1.
/// - parameter rect:   The `CGRect` within which that point should be converted.

private func convert(point point: CGPoint, rect: CGRect) -> CGPoint {
    return CGPoint(
        x: rect.origin.x + point.x * rect.size.width,
        y: rect.origin.y + rect.size.height - point.y * rect.size.height
    )
}

func sinePath(in rect: CGRect, count: Int? = nil) -> UIBezierPath {
    // note, since sine returns values between -1 and 1, let's add 1 and divide by two to get it between 0 and 1
    return path(in: rect, count: count) { (sin([=15=] * CGFloat(M_PI * 2.0)) + 1.0) / 2.0 }
}

/// Build path within rectangle
///
/// Given a `function` that converts values between zero and one to another values between zero and one, this method will create `UIBezierPath` within `rect` using that `function`.
///
/// - parameter rect:      The `CGRect` of points on the screen.
///
/// - parameter count:     How many points should be rendered. Defaults to `rect.size.width`.
///
/// - parameter function:  A closure that will be passed an floating point number between zero and one and should return a `CGPoint` with `x` and `y` values between 0 and 1.

private func parametricPath(in rect: CGRect, count: Int? = nil, function: (CGFloat) -> (CGPoint)) -> UIBezierPath {
    let numberOfPoints = count ?? max(Int(rect.size.width), Int(rect.size.height))

    let path = UIBezierPath()
    let result = function(0)
    path.moveToPoint(convert(point: CGPoint(x: result.x, y: result.y), rect: rect))
    for i in 1 ..< numberOfPoints {
        let t = CGFloat(i) / CGFloat(numberOfPoints - 1)
        let result = function(t)
        path.addLineToPoint(convert(point: CGPoint(x: result.x, y: result.y), rect: rect))
    }
    return path
}

func verticalSinePath(in rect: CGRect, count: Int? = nil) -> UIBezierPath {
    // note, since sine returns values between -1 and 1, let's add 1 and divide by two to get it between 0 and 1
    return parametricPath(in: rect, count: count) { CGPoint(
        x: (sin([=15=] * CGFloat(M_PI * 2.0)) + 1.0) / 2.0,
        y: [=15=]
    ) }
}

func spiralPath(in rect: CGRect, count: Int? = nil) -> UIBezierPath {
    return parametricPath(in: rect, count: count) { t in
        let r = 1.0 - sin(t * CGFloat(M_PI_2))
        return CGPoint(
            x: (r * sin(t * 10.0 * CGFloat(M_PI * 2.0)) + 1.0) / 2.0,
            y: (r * cos(t * 10.0 * CGFloat(M_PI * 2.0)) + 1.0) / 2.0
        )
    }
}

如何创建波路径 Swift

How to create a wave path Swift

trigonometry

cgpath

sprite-kit

swift2