将键盘表示为 3D 数组

Question

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相关代码如下：

此代码将键盘初始化为 3d 数组：

KeyboardRow1 = ["`", "1", "2", "3", "4", "5", "6", "7", "8", "9", "0", "-", "="]
KeyboardRow2 = ["", "q", "w", "e", "r", "t", "y", "u", "i", "o", "p", "[", "]", ""]
KeyboardRow3 = ["", "a", "s", "d", "f", "g", "h", "j", "k", "l", ";", ""] 
KeyboardRow4 = ["", "z", "x", "c", "v", "b", "n", "m", ",", ".", "/"]
KeyboardRow1S = ["~", "!", "@", "#", "$", "%", "^", "&", "*", "(", ")", "_", "+"]
KeyboardRow2S = ["", "Q", "W", "E", "R", "T", "Y", "U", "I", "O", "P", "{", "}", "|"]
KeyboardRow3S = ["","A", "S", "D", "F", "G", "H", "J", "K", "L", ":", ""] 
KeyboardRow4S = ["", "Z", "X", "C", "V", "B", "N", "M", "<", ">", "?", ""]
Array2R = [KeyboardRow1, KeyboardRow2, KeyboardRow3, KeyboardRow4]
Array2S = [KeyboardRow1S, KeyboardRow2S, KeyboardRow3S, KeyboardRow4S]
Array3 = [Array2R, Array2S]

此代码要求用户输入字符串：

Password = getpass.getpass("Enter a password: ")

此代码查找密码的每个字符在数组中的位置，并将其在数组中的坐标值附加到 KeyboardPositions

i = 0
j = 0
k = 0
z = 0
KeyboardPositions = []

for z in range(0,PasswordLength):

    for i in range(0,1):

        if Password[z] == str(Array3[i][j][k]):
            KeyboardPositions.append((i,j,k))

        for j in range(0,2):

            if Password[z] == str(Array3[i][j][k]):
                KeyboardPositions.append((i,j,k))

            for k in range (0,12):

                if Password[z] == str(Array3[i][j][k]):
                    KeyboardPositions.append((i,j,k))

当我运行代码时，它对键盘的前两行工作正常。如果密码是 qwerty，数组的内容（如预期的那样）是 [(0,1,1),(0,1,2),(0,1,3),(0,1,4),( 0,1,5),(0,1,6)]。三个坐标第一个是是否shift，第二个是行，第三个是列。

如果我输入 asdfg 、 zxcvb 或 ASD 之类的内容，它将无法工作。 KeyboardPositions 将为空。第三行或第四行的任何内容以及任何保留班次的内容都将不起作用。

Answer 1

问题出在您的 range 参数上。其中有几个错误。请记住，range(0, n) 从 0 到 n-1，不包括 n 本身。所以 range(0,1) 只包括 0。对于 range(0,2)，我假设您想从 0 迭代到 3，包括在内，所以您想要 range(0,4)，或者只是 range(4).

将键盘表示为 3D 数组

Representing keyboard as 3D array

python

arrays

keyboard

data-structures