模式匹配 (Any, Any) as (String, String) 在 Switch Case 中失败

Question

在以下代码方面需要帮助。

let first: Any = "One"
let second: Any = "Two"
let values = (first, second)

switch values {
case let (x, y) as (String, String):
    print("Success", x, y)
default:
    print("Failure")
}

switch first {
case let x as String:
   print("Success", x)
default:
   print("Failure")
}

--- 输出

Failure
Success One

--- 预期输出

Success One Two
Success One

演示：http://swiftstub.com/65065637

Answer 1

据我所知，您的转换有误。

以下是我对您的代码所做的更改，以使其正常工作：

let first: Any = "One"
let second: Any = "Two"
let values = (first, second)

switch values {
case let (x as String, y as String):
    print("Success", x, y)
default:
    print("Failure")
}

switch first {
case let x as String:
    print("Success", x)
default:
    print("Failure")
}

输出：

Success One Two
Success One

希望对您有所帮助！

模式匹配 (Any, Any) as (String, String) 在 Switch Case 中失败

Pattern Matching (Any, Any) as (String, String) Fails in Switch Case

string

switch-statement

swift

swift2