Android SimpleDateFormat 在午夜和凌晨 1 点之间返回不正确的时间

Question

已解决我发现在午夜和凌晨 1 点之间，我的设备 returns 是 1 小时后的时间（其他 23 小时是每天 returns 正确）。更奇怪的是，如果我使用 kk 而不是 HH，它 returns 正确（尽管生成的字符串对我没有用）

我的代码运行：（在本例中 strFormat 匹配 df3 中的硬编码字符串）

SimpleDateFormat df = new SimpleDateFormat(strFormat, Locale.US);
SimpleDateFormat df2 = new SimpleDateFormat("yyyy-MM-dd kk:mm", Locale.US);
SimpleDateFormat df3 = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS", Locale.US);

Date d = c.getTime();
String s = d.toString();
String ret = df.format(c.getTime());
String ret2 = df.format(new Date(System.currentTimeMillis()));
String ret3 = df2.format(c.getTime());
String ret4 = df3.format(c.getTime());
String r1 = ""+c.get(Calendar.HOUR);

这些return：

s = "Thu Jan 07 00:39:32 GMT-11:00 2016"
ret = "2016-01-07 01:39:32"
ret2 = "2016-01-07 01:39:32"
ret3 = "2016-01-07 24:39"
ret4 = "2016-01-07 01:39:32.525"
r1 = "0"

凌晨 1 点后 return:

s = "Thu Jan 07 01:07:09 GMT-11:00 2016"
ret = "2016-01-07 01:07:09"
ret2 = "2016-01-07 01:07:09"
ret3 = "2016-01-07 01:07"
ret4 = "2016-01-07 01:07:09.606"
r1 = "1"

我所做的任何帮助 wrong/what 都出错了，非常感谢。

更新

将代码更改为：

SimpleDateFormat df = new SimpleDateFormat(strFormat, Locale.US);
        df.setTimeZone(TimeZone.getTimeZone("GMT"));
        SimpleDateFormat df2 = new SimpleDateFormat("yyyy-MM-dd kk:mm zzz", Locale.US);
        df2.setTimeZone(TimeZone.getTimeZone("GMT"));
        SimpleDateFormat df3 = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS zzz", Locale.US);
        df3.setTimeZone(TimeZone.getTimeZone("GMT"));
        Date d = c.getTime();
        String s = d.toString();
        String ret = df.format(c.getTime());
        String ret2 = df.format(new Date(System.currentTimeMillis()));
        String ret3 = df2.format(c.getTime());
        String ret4 = df3.format(c.getTime());
        String r1 = ""+c.get(Calendar.HOUR);
        return ret;

我得到相同的结果：

s = "Fri Jan 08 00:52:05 GMT 2016"
ret = "2016-01-08 01:52:05"
ret2 = "2016-01-08 01:52:05"
ret3 = "2016-01-08 24:52 GMT"
ret4 = "2016-01-08 01:52:05.169 GMT"
r1 = "0"

和

s = "Fri Jan 08 01:03:23 GMT 2016"
ret = "2016-01-08 01:03:23"
ret2 = "2016-01-08 01:03:23"
ret3 = "2016-01-08 01:03 GMT"
ret4 = "2016-01-08 01:03:23.547 GMT"
r1 = "1"

所以问题似乎与时区无关

Answer 1

Idk...老实说。我尝试重现您的问题，但在 PC 上的 Eclipse 中，而不是在 Android 中。这是我使用的：

    Calendar c = new GregorianCalendar(TimeZone.getTimeZone(ZoneId.ofOffset("", ZoneOffset.ofHours(-11))), Locale.US);
    c.set(2016, 0, 7, 0, 7);

    String strFormat = "yyyy-MM-dd HH:mm:ss.SSS";


    SimpleDateFormat df = new SimpleDateFormat(strFormat, Locale.US);
    SimpleDateFormat df2 = new SimpleDateFormat("yyyy-MM-dd kk:mm", Locale.US);
    SimpleDateFormat df3 = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS", Locale.US);

    Date d = c.getTime();
    String s = d.toString();
    String ret = df.format(c.getTime());
    String ret2 = df.format(new Date(System.currentTimeMillis()));
    String ret3 = df2.format(c.getTime());
    String ret4 = df3.format(c.getTime());
    String r1 = ""+c.get(Calendar.HOUR);

    System.out.printf("s = %s%nret = %s%nret2 = %s%nret3 = %s%nret4 = %s%nr1 = %s%n%n", s, ret, ret2, ret3, ret4, r1);

    df.setTimeZone(TimeZone.getTimeZone(ZoneId.ofOffset("", ZoneOffset.ofHours(-11))));
    df2.setTimeZone(TimeZone.getTimeZone(ZoneId.ofOffset("", ZoneOffset.ofHours(-11))));
    df3.setTimeZone(TimeZone.getTimeZone(ZoneId.ofOffset("", ZoneOffset.ofHours(-11))));

    d = c.getTime();
    s = d.toString();
    ret = df.format(c.getTime());
    ret2 = df.format(new Date(System.currentTimeMillis()));
    ret3 = df2.format(c.getTime());
    ret4 = df3.format(c.getTime());
    r1 = ""+c.get(Calendar.HOUR);

    System.out.printf("s = %s%nret = %s%nret2 = %s%nret3 = %s%nret4 = %s%nr1 = %s%n%n", s, ret, ret2, ret3, ret4, r1);

    c.set(2016, 0, 7, 1, 7);

    d = c.getTime();
    s = d.toString();
    ret = df.format(c.getTime());
    ret2 = df.format(new Date(System.currentTimeMillis()));
    ret3 = df2.format(c.getTime());
    ret4 = df3.format(c.getTime());
    r1 = ""+c.get(Calendar.HOUR);

    System.out.printf("s = %s%nret = %s%nret2 = %s%nret3 = %s%nret4 = %s%nr1 = %s%n", s, ret, ret2, ret3, ret4, r1);

这就是我得到的：

s = Thu Jan 07 12:07:58 CET 2016
ret = 2016-01-07 12:07:58.662
ret2 = 2016-01-07 17:55:58.697
ret3 = 2016-01-07 12:07
ret4 = 2016-01-07 12:07:58.662
r1 = 0

s = Thu Jan 07 12:07:58 CET 2016
ret = 2016-01-07 00:07:58.662
ret2 = 2016-01-07 05:55:58.718
ret3 = 2016-01-07 24:07
ret4 = 2016-01-07 00:07:58.662
r1 = 0

s = Thu Jan 07 13:07:58 CET 2016
ret = 2016-01-07 01:07:58.662
ret2 = 2016-01-07 05:55:58.722
ret3 = 2016-01-07 01:07
ret4 = 2016-01-07 01:07:58.662
r1 = 1

也许你的 SimpleDateFormat 有问题，它使用了不同的时区......这真的很有趣。

Answer 2

可能： c.getTime() returns 您的当前时间，SimpleDateFormat 将其格式化为 Locale.US。美国是一个拥有不同时区的大国，您的设备时区可能与 Locale.US 不同！删除 Locale.US 并随时通知我们。

Answer 3

可能您必须为 dateFormat 对象设置时区。

我试过这个：

    Calendar c = new GregorianCalendar(TimeZone.getTimeZone("GMT-11:00"), Locale.US);
    c.set(2016, 0, 7, 00, 39, 32);
    Date date  = c.getTime();

    SimpleDateFormat df = new SimpleDateFormat("EEE MMM dd HH:mm:ss zzz yyyy", Locale.US);
    df.setTimeZone(TimeZone.getTimeZone("GMT-11:00"));
    SimpleDateFormat df2 = new SimpleDateFormat("yyyy-MM-dd kk:mm", Locale.US);
    df2.setTimeZone(TimeZone.getTimeZone("GMT-11:00"));
    SimpleDateFormat df3 = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS", Locale.US);
    df3.setTimeZone(TimeZone.getTimeZone("GMT-11:00"));

    String ret = df.format(date.getTime());
    String ret2 = df.format(date.getTime());
    String ret3 = df2.format(date.getTime());
    String ret4 = df3.format(date.getTime());

    System.out.println("  ret : "+ret);
    System.out.println("  ret2 : "+ret2);
    System.out.println("  ret3 kk: "+ret3);
    System.out.println("  ret4 : "+ret4);

结果正确：

 ret : Thu Jan 07 00:39:32 GMT-11:00 2016
 ret2 : Thu Jan 07 00:39:32 GMT-11:00 2016
 ret3 kk: 2016-01-07 24:39
 ret4 : 2016-01-07 00:39:32.217

Answer 4

问题出在平板电脑本身 - 它们内置了额外的传感器，一旦访问就会扰乱内部时钟。感谢大家的帮助

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