C++ 运算符用指针重载

Question

struct Test {
    int A = 0;
    int B = 0;
};

Test* operator+(const Test *x, const Test *r) {

    Test *test = new Test;
    test->A = x->A + r->A;
    test->B = x->B + r->B;
    return test;
}

为什么这不起作用并给出：

3 IntelliSense: nonmember operator requires a parameter with class or enum type

Answer 1

显然，operator+ 要求第一个参数不是指针。这会起作用：

Test* operator+(const Test &x, const Test& r){

    Test *test = new Test;
    test->A = x.A + r.A;
    test->B = x.B + r.B;
    return test;
}

但是如果你不 return 指针会更安全，就像 Jonachim 说的那样。你应该这样做：

Test operator+(const Test &x, const Test& r){

    Test test;
    test.A = x.A + r.A;
    test.B = x.B + r.B;
    return test;
}

C++ 运算符用指针重载

C++ operator overloading with pointers

c++

operator-overloading