Android 中的拖放：如何获得拖放视图的新位置

Question

嗨，我得到了一个简单的拖放 activity。它看起来像这样：

public class Test extends Activity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_test);

    findViewById(R.id.myimage1).setOnTouchListener(new MyTouchListener());
    findViewById(R.id.myimage2).setOnTouchListener(new MyTouchListener());
    findViewById(R.id.myimage3).setOnTouchListener(new MyTouchListener());
    findViewById(R.id.myimage4).setOnTouchListener(new MyTouchListener());
    findViewById(R.id.one).setOnDragListener(new MyDragListener());
    findViewById(R.id.two).setOnDragListener(new MyDragListener());
    findViewById(R.id.three).setOnDragListener(new MyDragListener());
    findViewById(R.id.four).setOnDragListener(new MyDragListener());
}


//TEST DRAG AND DROP

private final class MyTouchListener implements View.OnTouchListener {
    public boolean onTouch(View view, MotionEvent motionEvent) {
        if (motionEvent.getAction() == MotionEvent.ACTION_DOWN) {
            ClipData data = ClipData.newPlainText("", "");
            View.DragShadowBuilder shadowBuilder = new View.DragShadowBuilder(view);
            view.startDrag(data, shadowBuilder, view, 0);
            view.setVisibility(View.INVISIBLE);
            return true;
        } else {
            return false;
        }
    }
}

class MyDragListener implements View.OnDragListener {
    Drawable enterShape = getResources().getDrawable(R.drawable.shape_droptarget);
    Drawable normalShape = getResources().getDrawable(R.drawable.shape);

    @Override
    public boolean onDrag(View v, DragEvent event) {
        int action = event.getAction();
        switch (event.getAction()) {
            case DragEvent.ACTION_DRAG_STARTED:
                // do nothing
                break;
            case DragEvent.ACTION_DRAG_ENTERED:
                v.setBackgroundDrawable(enterShape);
                break;
            case DragEvent.ACTION_DRAG_EXITED:
                v.setBackgroundDrawable(normalShape);
                break;
            case DragEvent.ACTION_DROP:
                // Dropped, reassign View to ViewGroup
                View view = (View) event.getLocalState();
                ViewGroup owner = (ViewGroup) view.getParent();
                owner.removeView(view);
                LinearLayout container = (LinearLayout) v;
                container.addView(view);
                view.setVisibility(View.VISIBLE);
                break;
            case DragEvent.ACTION_DRAG_ENDED:
                v.setBackgroundDrawable(normalShape);
            default:
                break;
        }
        return true;
    }
}

}

现在我想了解View onClick 的新位置。为此我需要一个整数。它可能是这样的：如果图片一在布局一中，则 int 为：“11”，如果图片二在布局 3 中，则 int 将为“23”。而我需要所有4张图片的位置，所以我需要4个int。

但我不知道，如何获得新职位。我感谢任何帮助！

Answer 1

当onClick被触发时，您可以通过调用int indexOfChild(View)简单地获取子视图位置：

@Override
public void onClick(View v) {
    int position = parentContainer.indexOfChild(v);
}

然后，为每个小部件的图像添加特定标签。您将能够将您的 int 构造为 imageTag + position，例如：

@Override
public void onClick(View v) {
    String imageTag = v.getTag();
    int position = parentContainer.indexOfChild(v);

    int resultValue = Integer.parseInt(imageTag) + position;
}

Android 中的拖放：如何获得拖放视图的新位置

Drag and Drop in Android: How to get the new position of a dropped View

java

android

drag-and-drop

draggable