在 Python 2.7 中使用装饰方法调用发出模拟

Question

此代码：

import mock
from functools import wraps

def dec(f):
    @wraps(f)
    def f_2(*args, **kwargs):
        pass
    return f_2


class Example(object):
    def __init__(self):
        pass

    @dec
    def method_1(self, arg):
        pass

    def method_2(self, arg):
        self.method_1(arg)



def test_example():
    m = mock.create_autospec(Example)
    Example.method_2(m, "hello")
    m.method_1.assert_called_once_with("hello")

使用 py.test

产生此错误

    def test_example():
        m = mock.create_autospec(Example)
>       Example.method_2(m, "hello")

example.py:26: 
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
example.py:20: in method_2
    self.method_1(arg)
anaconda2/envs/arctic/lib/python2.7/site-packages/mock/mock.py:1061: in __call__
    _mock_self._mock_check_sig(*args, **kwargs)
anaconda2/envs/arctic/lib/python2.7/site-packages/mock/mock.py:227: in checksig
    sig.bind(*args, **kwargs)
anaconda2/envs/arctic/lib/python2.7/site-packages/mock/mock.py:95: in fixedbind
    return self._bind(args, kwargs)
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _

self = <funcsigs.Signature object at 0x7f09b8685e10>, args = ('hello',), kwargs = {}, partial = False

    def _bind(self, args, kwargs, partial=False):
        '''Private method.  Don't use directly.'''
        arguments = OrderedDict()

        parameters = iter(self.parameters.values())
        parameters_ex = ()
        arg_vals = iter(args)

        if partial:
            # Support for binding arguments to 'functools.partial' objects.
            # See 'functools.partial' case in 'signature()' implementation
            # for details.
            for param_name, param in self.parameters.items():
                if (param._partial_kwarg and param_name not in kwargs):
                    # Simulating 'functools.partial' behavior
                    kwargs[param_name] = param.default

        while True:
            # Let's iterate through the positional arguments and corresponding
            # parameters
            try:
                arg_val = next(arg_vals)
            except StopIteration:
                # No more positional arguments
                try:
                    param = next(parameters)
                except StopIteration:
                    # No more parameters. That's it. Just need to check that
                    # we have no `kwargs` after this while loop
                    break
                else:
                    if param.kind == _VAR_POSITIONAL:
                        # That's OK, just empty *args.  Let's start parsing
                        # kwargs
                        break
                    elif param.name in kwargs:
                        if param.kind == _POSITIONAL_ONLY:
                            msg = '{arg!r} parameter is positional only, ' \
                                  'but was passed as a keyword'
                            msg = msg.format(arg=param.name)
                            raise TypeError(msg)
                        parameters_ex = (param,)
                        break
                    elif (param.kind == _VAR_KEYWORD or
                                                param.default is not _empty):
                        # That's fine too - we have a default value for this
                        # parameter.  So, lets start parsing `kwargs`, starting
                        # with the current parameter
                        parameters_ex = (param,)
                        break
                    else:
                        if partial:
                            parameters_ex = (param,)
                            break
                        else:
                            msg = '{arg!r} parameter lacking default value'
                            msg = msg.format(arg=param.name)
                            raise TypeError(msg)
            else:
                # We have a positional argument to process
                try:
                    param = next(parameters)
                except StopIteration:
                    raise TypeError('too many positional arguments')
                else:
                    if param.kind in (_VAR_KEYWORD, _KEYWORD_ONLY):
                        # Looks like we have no parameter for this positional
                        # argument
>                       raise TypeError('too many positional arguments')
E                       TypeError: too many positional arguments

anaconda2/envs/arctic/lib/python2.7/site-packages/funcsigs/__init__.py:716: TypeError

有什么方法可以测试这段代码的意图吗？如果您删除装饰器，或者如果您将参数设置为 method_1 关键字参数，它会神奇地起作用。我不确定这个错误是在 Mock 本身，还是在 funcsigs 中，但显然有些地方不对劲。有解决方法吗？另一种测试 method_2 调用 method_1 ?

的方法

我应该提一下，这是模拟 1.3.0。由于某种原因，此代码在 1.0.1 中有效，但我需要使用最新版本的 mock。

更新

这个有效：

def test_example():
    m = mock.Mock(spec=Example)
    m.method_1 = mock.Mock()
    Example.method_2(m, "hello")
    m.method_1.assert_called_once_with("hello")

Answer 1

从 mock 1.1.0 开始，框架开始深入检查方法签名。看看 changelog 在

Issue #17015: When it has a spec, a Mock object now inspects its signature when matching calls, so that arguments can be matched positionally or by name

现在，如果您将 f2() 签名更改为 def f_2(arg, *args, **kwargs)，它应该可以工作。

也许这是一个新错误，签名检查无法正确理解调用是否正确（至少兼容）。我认为您可以在此处提交错误和 post 票证 link.

作为解决方法，您可以通过添加

从 method_1 中删除自动指定

m.method_1 = mock.Mock()

在 Python 2.7 中使用装饰方法调用发出模拟

Issue mocking with a decorated method call in Python 2.7

python

unit-testing

mocking

pytest

python-2.7