从 python 中的列表和字典嵌套中删除任意元素
remove an arbitrary element from a nest of lists and dicts in python
a = [
{
'b':[1,2,3]
},{
'c':{
'd':'e',
'f':'g'
}
}
]
b = [0,'b',2]
c = [2,'c','f']
上面我想用b或c中包含的键来销毁a中对应的元素。在这种情况下，del a[1]['b'][2] 代表 a，或 a[2]['c'].pop('f') 代表 c。
在给定任意深度和树结构的情况下，是否有一种干净的方法可以做到这一点？
def nested_del(structure, del_spec):
for item in del_spec[:-1]: # Loop through all but the last element.
structure = structure[item] # Go further into the nested structure
del structure[del_spec[-1]] # Use the last element to delete the desired value
nested_del(a, b)
nested_del(a, c)
a = [
{
'b':[1,2,3]
},{
'c':{
'd':'e',
'f':'g'
}
}
]
b = [0,'b',2]
c = [2,'c','f']
上面我想用b或c中包含的键来销毁a中对应的元素。在这种情况下，del a[1]['b'][2] 代表 a，或 a[2]['c'].pop('f') 代表 c。
在给定任意深度和树结构的情况下，是否有一种干净的方法可以做到这一点？
def nested_del(structure, del_spec):
for item in del_spec[:-1]: # Loop through all but the last element.
structure = structure[item] # Go further into the nested structure
del structure[del_spec[-1]] # Use the last element to delete the desired value
nested_del(a, b)
nested_del(a, c)