Jersey JAX-RS 独立服务器 - 如何将参数传递给请求处理程序?

Jersey JAX-RS standalone server - how pass parameters to request handler?

我构建了一个简单的 Jersey rest 服务器,用于处理简单的服务。 在启动服务器的 main class 中,我读取了我想要的属性文件 provide/pass 到 jax 处理程序 classes。 服务器工作,我只需要想办法共享配置参数 main class 带有请求处理程序。 我该怎么做?


main代码,我只读了一次de属性文件:

...

public HashMap resources;

// this start the listener jersey server...
String host="http://localhost/";
int port = 9998;
URI baseUri = UriBuilder.fromUri(host).port(port).build();
ResourceConfig config = new ResourceConfig();
config.packages(true, "br.com.myserver");
config.register(MyHandler.class);

// I WANT TO ACCESS/SHARE THIS WITH THE HANDLER -> MyHandler.class
resources.put("host_user","bla bla bla");

HttpServer server = JdkHttpServerFactory.createHttpServer(baseUri, config);

System.out.println("--Press Enter to STOP the server--");
System.in.read();
Server.stop(0);
System.out.println("Server stoped!");
...

MyHandler 的代码,我想在其中访问主要属性:

@Path("myapp")
public class MyHandler
{
    @POST @Path("/testep")
    @Consumes("application/json")
    @Produces("text/plain")
    public String action1(@Context Request request, String json) 
    {
        // HERE I WANT TO ACCESS THE RESOUCES HASHMAP OF MAIN HERE
        // (how get main handler here).resources.get("host_user");

        // maybe access main class, or something like
        // the intention is to avoid the read of config at all requests here

        System.out.println("received event:" + json);
        return "event received " + json;
    }
}

任何想法将不胜感激,谢谢。

您使用 property(key, value) 配置 ResourceConfig 的任何属性都可以通过 Configuration 接口访问,您可以将其注入资源 class.

ResourceConfig config = new ResourceConfig();
config.property("host_user","bla bla bla");
...
@Path("myapp")
public class MyHandler
{
    @Context
    Configuration configuration;

    public String action1(@Context Request request, String json) {
        Map<String, Object> props = configuration.getProperties();
    }
}

另请参阅: