Java switch - 在缺少 break 后执行了不正确的 case。为什么？

Question

我在网上学习 Java 并在 switch 上来上课。为了愚弄，我删除了特定案例（将被执行）之后的一个中断。我原以为它会检查下一个案例，看到条件为假，然后在退出前跳到默认案例。相反，它执行了错误的案例并在默认案例之前中断。

这里出了什么问题？

public class Switch {
    public static void main(String[] args) {

        char penaltyKick = 'R';

        switch (penaltyKick) {

            case 'L': System.out.println("Messi shoots to the left and scores!");
                                break; 
            case 'R': System.out.println("Messi shoots to the right and misses the goal!");

            case 'C': System.out.println("Messi shoots down the center, but the keeper blocks it!");
                                break;
            default:
                System.out.println("Messi is in position...");

        }

    }
}

编辑：忘了说了。输出是：

Messi shoots to the right and misses the goal! 
Messi shoots down the center, but the keeper blocks it!

Answer 1

如果缺少 break，执行将跳转到下一个 case，而不会再次检查条件。参见 here：

The break statements are necessary because without them, statements in switch blocks fall through: All statements after the matching case label are executed in sequence, regardless of the expression of subsequent case labels, until a break statement is encountered.

Java switch - 在缺少 break 后执行了不正确的 case。为什么？

Java switch - incorrect case executed after missing break. Why?

java

switch-statement