如何在hql中编写group by？

Question

我写了一个这样的hql：

select DATE_FORMAT(createAt, '%Y-%m-%d') as day, sum(amount) as orderAmount 
    from FoodOrder where deleted = 'false' and orderState = ?1
    and createAt between ?2 and ?3 group by day order by day

我收到错误：'group statement' 中的未知列 'day'。

休眠日志是这样的：

select
    date_format(foodorder0_.create_at,
    '%Y-%m-%d') as col_0_0_,
    sum(foodorder0_.amount) as col_1_0_
from
    food_order foodorder0_
where
    foodorder0_.deleted='false'
    and foodorder0_.order_state=?
    and (
        foodorder0_.create_at between ? and ?
    )
group by
    day
order by
    col_0_0_

为什么使用 col_0_0_ 排序但使用 "day" 分组却出现错误？

任何帮助谢谢！

Answer 1

是的，按照Bonifacio的回答，应该是：

group by DATE_FORMAT(createAt, '%Y-%m-%d')

抱歉评论晚了，这次我不能将 Bonifacio 设置为最佳答案。

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