检查从 preg_replace() 返回的值是否存在于数组中

Question

我有一个消息字符串例如：

$data="Hey my dear :laugh: how are you :mmmmm: :smile: and non existing smile :go: ";

我有微笑数组（用于检查）

$smileys=array("laugh","mmmm","smile");

昨天朋友帮我把:smile:类型转换成喜欢下

$data=preg_replace("/:([a-zA-Z]+):/","<img src='images/smileys/.png' class='smile'>",$data);

我如何检查数组中是否存在这个微笑？

示例：http://masters.az
login:test
pass:test
代码示例：http://masters.az/message-3

Answer 1

您可以使用 in_array() 函数。解释是here

那你应该试试这个:-

    $data="Hey my dear :laugh: how are you :mmmmm: :smile: and non existing smile :go: ";
$smileys=array("laugh","mmmm","smile");
foreach ($smileys as $sm)
{
    $data1=preg_replace("/:([a-zA-Z]+):/",$sm,"<img src='images/smileys/.png' class='smile'>");
    if(stristr($data,$sm))
    {
       echo $sm." matched"."<br>";
    }
}

参考是Here

Answer 2

您可以使用 preg_replace_callback:

$data = "Hey my dear :laugh: how are you :mmmmm: :smile: and non existing smile :go: ";
$smileys = array("laugh","mmmm","smile");
$data = preg_replace_callback("/:([a-zA-Z]+):/",
    function ($m) use($smileys) {
        if (in_array($m[1], $smileys) )
            return "<img src='images/smileys/$m[1].png' class='smile'>";

    },
    $data);
echo $data,"\n";

输出：

Hey my dear <img src='images/smileys/laugh.png' class='smile'> how are you  <img src='images/smileys/smile.png' class='smile'> and non existing smile

Answer 3

我会用 or 分解术语，然后在替换中使用找到的术语。

$data = "Hey my dear :laugh: how are you :mmmmm: :smile: and non existing smile :go: ";
$smileys = array("laugh","mmmm","smile");
echo preg_replace('/:(' . implode('|', $smileys) . '):/', '<img src="images/smileys/.png" class="">', $data);

PHP 演示：https://eval.in/511095

Regex101 演示：https://regex101.com/r/hI1aX0/1

这是一个 JS 方法：

var test = ["laugh","mmmm","smile"];
var regex = new RegExp(':(' + test.join('|') + '):', 'g');
var string = "Hey my dear :laugh: how are you :mmmmm: :smile: and non existing smile :go: ";
var string = string.replace(regex, '<img src="images/smileys/.png" class="">');
console.log(string);
console.log(regex);

演示：https://jsfiddle.net/8fj00bg5/

检查从 preg_replace() 返回的值是否存在于数组中

Check value returning from preg_replace() exists or no in array

javascript

php

regex

preg-replace