用户输入的脚本

Question

我正在尝试运行一个询问用户最喜欢的运动队的脚本。这是我目前所拥有的：

print("Who is your favorite sports team: Yankees, Knicks, or Jets?")
if input is "Yankees":
    print("Good choice, go Yankees")
elif input is "Knicks":
    print("Why...? They are terrible")
elif input is "Jets":
    print("They are terrible too...")
else:
    print("I have never heard of that team, try another team.")

每当我运行这个脚本时，最后一个 "else" 函数会在用户输入任何内容之前接管。

此外，none 个可供选择的团队已定义。有帮助吗？

Answer 1

输入是一个要求用户回答的函数。

您需要调用它并将 return 值分配给某个变量。

然后检查那个变量，而不是 input 本身。

备注你可能想要 raw_input() 而不是得到你想要的字符串。

记得去除空格。

Answer 2

您的主要问题是您正在使用 is 来比较值。正如这里的问题所讨论的那样 --> String comparison in Python: is vs. ==

You use == when comparing values and is when comparing identities.

您可能希望将代码更改为如下所示：

print("Who is your favorite sports team: Yankees, Knicks, or Jets?")
if input == "Yankees":
    print("Good choice, go Yankees")
elif input == "Knicks":
    print("Why...? They are terrible")
elif input == "Jets":
    print("They are terrible too...")
else:
    print("I have never heard of that team, try another team.")

但是，您可能需要考虑将您的代码放入 while 循环中，以便向用户询问问题，直到您的答案被接受为止。

您可能还需要考虑添加一些人为错误容忍度，方法是将比较值强制转换为小写字母。这样只要队名拼写正确，他们的对比就会准确无误。

例如，看下面的代码：

while True: #This means that the loop will continue until a "break"
    answer = input("Who is your favorite sports team: Yankees, Knicks, or Jets? ").lower() 
#the .lower() is where the input is made lowercase
    if answer == "yankees":
        print("Good choice, go Yankees")
        break
    elif answer == "knicks":
        print("Why...? They are terrible")
        break
    elif answer == "jets":
        print("They are terrible too...")
        break
    else:
        print("I have never heard of that team, try another team.")

用户输入的脚本

User inputted script

python

python-3.x