如何将字符串转换为 char 以填充 Java 中的数组？

Question

如标题所述，我希望创建一个 char 数组，用户输入应存储为 char。我这样做是为了创建有缺陷的代码，这些代码可能会成为缓冲区溢出的牺牲品。在我完成这项工作后，我将截断输入并且不会导致缓冲区溢出。但是当我被指示这样做时，我无法弄清楚如何将我的字符串存储为 Java 中的 char。这是我到目前为止的代码：

import java.util.Scanner;





public class buggyCode {

public buggyCode() {
    // TODO Auto-generated constructor stub
}

public static void main(String[] args) {
    // TODO Auto-generated method stub
    Scanner kb = new Scanner(System.in);
    String input1, input2, input3, input4, input5, input6, input7, input8, input9, input10;
    char[] thisArray = new char [150];

    thisArray[0]=toChar(input1);
    thisArray[1]=input2;
    thisArray[3]=input3;


    System.out.println("Enter some characters. We are going to do this for a while");
    input1 = kb.nextLine();
    System.out.println("Enter some characters. We are going to do this for a while");
    input2 = kb.nextLine();
    System.out.println("Enter some characters. We are going to do this for a while");
    input3 = kb.nextLine();
    System.out.println("Enter some characters. We are going to do this for a while");
    input4 = kb.nextLine();
    System.out.println("Enter some characters. We are going to do this for a while");
    input5 = kb.nextLine();
    System.out.println("Enter some characters. We are going to do this for a while");
    input6 = kb.nextLine();
    System.out.println("Enter some characters. We are going to do this for a while");
    input7 = kb.nextLine();
    System.out.println("Enter some characters. We are going to do this for a while");
    input8 = kb.nextLine();
    System.out.println("Enter some characters. We are going to do this for a while");
    input9 = kb.nextLine();
    System.out.println("Enter some characters. We are going to do this for a while");
    input10 = kb.nextLine();

}

}

Answer 1

首先，这行代码会在启动程序时自动失败删除：

thisArray[0]=toChar(input1);
thisArray[1]=input2;
thisArray[3]=input3;

要获得干净的代码，您可以放弃使用字符串并使用 for loop

循环它们

for(int i = 0; i < 10; i++)
{
    System.out.println("Enter some characters. We are going to do this for a while");
    thisArray[i] = kb.nextLine().toCharArray()[0]; //store the first index of string to the thisArray array
}

上面你可以看到 nextLine() 然后被转换为 char 数组并获得第一个索引，然后存储在你的 char 数组中

Answer 2

每次你写 inputN 两次以上，用数字代替 N，你就知道你需要一个数组。大多数时候，当您发现自己在复制粘贴代码时只做了很少的改动，您就知道您需要一个循环。

I am to fill the array at every 10 indices starting at 150 going down.

正确的做法如下：

char[] input = new char[150];
for (int i = 0 ; i != 10 ; i++) {
    System.out.println("Enter some characters. We are going to do this for a while.");
    char[] buf = kb.nextLine().toCharArray();
    // Copy the data into input
    System.arraycopy(buf, 0, input, 140-(i*10), Math.min(buf.length, 10));
}

如何将字符串转换为 char 以填充 Java 中的数组？

How to cast a string to a char to fill an array in Java?

java

arrays

security