测试 preg_replace 不工作
tested preg_replace not working
我有以下
$string = 'Trials <- load.dataset("Foo, Bar")';
$pattern[0] = "/(?:load.dataset|\"Foo, Bar?)\"/";
$replacement[0] = '"/my/path/JohnDoe.csv"';
preg_replace($pattern, $replacement, $string);
echo $pattern[0]; // /(?:load.dataset|"Foo, Bar?)"/
echo $replacement[0]; // "/my/path/JohnDoe.csv"
但是,替代品看起来不起作用;
echo $string; // Trials <- load.dataset("Foo, Bar")
我已经用 PHP Live Regex 测试了我的正则表达式,它在那里工作正常,所以我不确定我在哪里犯了错误。
为什么没有发生替换?
preg_replace
需要分配给您的变量。
是这样的:
$string = 'Trials <- load.dataset("Foo, Bar")';
$pattern[0] = "/(?:load.dataset|\"Foo, Bar?)\"/";
$replacement[0] = '"/my/path/JohnDoe.csv"';
preg_replace($pattern, $replacement, $string);
即时替换,尝试更新为:
$string = preg_replace($pattern, $replacement, $string);
来自手册:
If matches are found, the new subject will be returned, otherwise subject will be returned unchanged or NULL if an error occurred.
我有以下
$string = 'Trials <- load.dataset("Foo, Bar")';
$pattern[0] = "/(?:load.dataset|\"Foo, Bar?)\"/";
$replacement[0] = '"/my/path/JohnDoe.csv"';
preg_replace($pattern, $replacement, $string);
echo $pattern[0]; // /(?:load.dataset|"Foo, Bar?)"/
echo $replacement[0]; // "/my/path/JohnDoe.csv"
但是,替代品看起来不起作用;
echo $string; // Trials <- load.dataset("Foo, Bar")
我已经用 PHP Live Regex 测试了我的正则表达式,它在那里工作正常,所以我不确定我在哪里犯了错误。
为什么没有发生替换?
preg_replace
需要分配给您的变量。
是这样的:
$string = 'Trials <- load.dataset("Foo, Bar")';
$pattern[0] = "/(?:load.dataset|\"Foo, Bar?)\"/";
$replacement[0] = '"/my/path/JohnDoe.csv"';
preg_replace($pattern, $replacement, $string);
即时替换,尝试更新为:
$string = preg_replace($pattern, $replacement, $string);
来自手册:
If matches are found, the new subject will be returned, otherwise subject will be returned unchanged or NULL if an error occurred.