列表理解中的测试和断言

Question

我是 python 测试的新手，如果可能的话，我想使用 pytest 来检查我的功能是否正确。有一个输入和预期输出列表：

    test_cases = [
        ("...Guide: From Mid .3ms", [(1300000)]),
        ("OFFERS OVER ,100,000", [(1100000)]),
        ("...Around .35million", [(1350000)]),
        ("Guide above .2m", [(1200000)]),
        ("...From .55 Million", [(2550000)]),
        ("Low  millions", [(2000000)]),
        ("Mid M's Buyers", [(2000000)]),
        ("5,000 - 9,950", [(305000), (349950)]),
        ("...5,000 and 0,000", [(485000), (510000)]),
        ("...High 0,000's", [(300000)]),
        ("...000 + to 5,000 +", [(625000)]),
        ("9k", [(299000)]),
        ("... Buyers Guide .29M+", [(1290000)]),
        ("m", [(1000000)]),
        (",000,000.00", [(1000000)])
        ]

如果将 test_cases[n][0] 作为输入，测试我的函数 returns test_cases[n][1] 的最优雅方法是什么？我能否以某种方式断言这一点，同时仍然获得有意义的结果（即 10 次测试中有 7 次成功完成，10 次测试中有 10 次成功完成）？

Answer 1

The parametrize decorator 这样做。您给它一个输入列表，它将运行对输入列表的每个元素进行一次修饰测试。每一个都将被报告为一个单独的测试。

import pytest

test_cases = [
    ("...Guide: From Mid .3ms", [(1300000)]),
    ("OFFERS OVER ,100,000", [(1100000)]),
    ("...Around .35million", [(1350000)]),
    ("Guide above .2m", [(1200000)]),
    ("...From .55 Million", [(2550000)]),
    ("Low  millions", [(2000000)]),
    ("Mid M's Buyers", [(2000000)]),
    ("5,000 - 9,950", [(305000), (349950)]),
    ("...5,000 and 0,000", [(485000), (510000)]),
    ("...High 0,000's", [(300000)]),
    ("...000 + to 5,000 +", [(625000)]),
    ("9k", [(299000)]),
    ("... Buyers Guide .29M+", [(1290000)]),
    ("m", [(1000000)]),
    (",000,000.00", [(1000000)])
]

@pytest.mark.parametrize("in, out", test_cases)
def test(in, out):
    assert f(in) == out

Answer 2

reduce 功能类似于其他函数式语言中的 fold 。这是对问题的功能性处理：

from functools import reduce
from operator import and_
def test():
    assert reduce(and_, [f(x) == y for x, y in test_cases])

列表理解中的测试和断言

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