如何在控制器中发送消息后弹出成功消息，使用c#，MVC

Question

我正在使用 smpt 发送电子邮件。我可以发送电子邮件 successfully.I 已经测试过了 received.now 我的问题是如何在完成电子邮件发送过程后显示成功或错误消息（到目前为止只有成功也足够）在 controller.I 已在此处附上我的控制器内的代码。

    [HttpPost]
    public async Task<ActionResult> GetEnquiryData(string FirstName, string LastName, string Email, string PhoneNumber, string TravelCalendar, string TravelNights, string TravelMonth, string TNoAdults, string TNoChildren, string SpecialOc, string GettoKnow, string TCUKMember, string Tdate, string Tprice, string byemail, string dealRef, string ConTime)
    {
        var firstName = FirstName;
        var lastName = LastName;
        var email = Email;
        var contactNumber = PhoneNumber;
        var travelCalendar = TravelCalendar;
        var travelNights = TravelNights;
        var travelMonth = TravelMonth;
        var TAdults = TNoAdults;
        var TChildren = TNoChildren;
        var SpecialOcc = SpecialOc;
        var GetToKnow = GettoKnow;
        var TcukMember = TCUKMember;
        var Date = Tdate;
        var Price = Tprice;
        var Mail_Call = byemail;
        var DealRef = dealRef;
        var CTime = ConTime;
        string subject = "";
        string body = "";


        //TCNewDBEntities EnquiryEntities = new TCNewDBEntities();
        //Enquiry enQuiryDetails = new Enquiry();

        //enQuiryDetails.FirstName = firstName;
        //enQuiryDetails.LastName = lastName;
        //enQuiryDetails.EmailAddress = email;


        //EnquiryEntities.Enquiries.Add(enQuiryDetails);
        //EnquiryEntities.SaveChanges();


        var fromAddress = "inone@Ubr.co.uk";
        subject = "Enquiry Form Details";
        body += "<br /><br /><b>" + Mail_Call + "</b>";
        body += "<br /><br />Deal Reference No." + DealRef;
        body += "<br /><br />First Name : " + firstName;
        body += "<br /><br />Last Name : " + lastName;
        body += "<br /><br />Email Address : " + email;
        body += "<br /><br />Contact Number : " + contactNumber;
        body += "<br /><br />Traveling From : " + travelCalendar;
        body += "<br /><br />Nights : " + travelNights;
        body += "<br /><br />Date : " + Date + " " + travelMonth;
        body += "<br /><br />Price : " + Price;
        body += "<br /><br />No. Adults : " + TAdults;
        body += "<br /><br />No. Children : " + TChildren;
        body += "<br /><br />Special Occasion : " + SpecialOc;
        body += "<br /><br />Know About Deals: " + GetToKnow;
        body += "<br /><br />Convenient Time:" + CTime;
        body += "<br /><br />Voucher Code: " + TcukMember;


        MailMessage mailP = new MailMessage();
        mailP.From = new MailAddress(fromAddress);
        mailP.To.Add(new MailAddress("abcd@gmail.com"));
        mailP.Bcc.Add(new MailAddress(email));
        mailP.Subject = "'" + subject + "'";
        mailP.Body = body;
        mailP.IsBodyHtml = true;

        using (var smtpClient = new SmtpClient())
        {
            var credential = new NetworkCredential
            {
                UserName = "smtpubr",
                Password = "12ubr34"
            };

            smtpClient.Credentials = credential;
            smtpClient.Host = "smtpttcorpeo.com";
            smtpClient.Port = 2322;
            smtpClient.EnableSsl = true;

            await smtpClient.SendMailAsync(mailP);
        }

        return Json(new { });
    }

希望得到你的帮助。

Answer 1

让你return像这样的对象示例

public class ServerResponse
{
public string ErrorMessage {get; set;}
public string SuccessMessage {get; set;}
}

然后

 public async Task<ActionResult> GetEnquiredData(string FirstName, string LastName, string Email, string PhoneNumber, string TravelCalendar, string TravelNights, string TravelMonth, string TNoAdults, string TNoChildren, string SpecialOc, string GettoKnow, string TCUKMember, string Tdate, string Tprice, string byemail, string dealRef, string ConTime)
 {
        var serverResponse = new ServerResponse();
        try { //Send Email here
        serverResponse.SuccessMessage = "Success!";
        }
        catch (Exception ex)
        {
        serverResponse.ErrorMessage= $"Error! + {ex.Message}";
        }
       return Json(serverResponse, JsonRequestBehaviour.AllowGet);
 }

在它通过 ajax 检查服务器响应后。并显示消息！希望对你有帮助

js

$.ajax({
url : /YourURL/GetEnquiredData,
data : {your data}
}).success(function(response)
{ if (response.ErrorMessage!=null)
{ 
showError(response.ErrorMessage):
}
else {
showSucess(response.SuccessMessage);
}

});

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