如何从 MySQL table 中获取 php 网络服务中的所有记录

Question

$sql=mysql_query("SELECT friendName,createdDate FROM friends where userId='$userId'");
$result=mysql_fetch_assoc($sql);
if(!empty($result))
{
$json=$result;
}
else
{
$json = array( "msg" => "No infomations Found");
}
header('Content-type: application/json');

我正在尝试使用 about 代码从数据库中获取所有值，但只有一条记录可以 come.please 帮助我

Answer 1

试试这个：

$sql=mysql_query("SELECT friendName,createdDate FROM friends where userId='$userId'");
$json= array();
while($json = mysql_fetch_assoc($sql)){}
if(empty($json))
{
    $json = array( "msg" => "No infomations Found");
}
header('Content-type: application/json');

Answer 2

参见下面的示例：

while($row = mysql_fetch_array($retval, MYSQL_ASSOC)) {
      echo "EMP ID :{$row['emp_id']}  <br> ".
         "EMP NAME : {$row['emp_name']} <br> ".
         "EMP SALARY : {$row['emp_salary']} <br> ".
         "--------------------------------<br>";
   }

Answer 3

首先停止使用 mysql_*，因为它现在已弃用库。使用 mysqli_* 或 PDO

其次，您需要按以下方式对返回的查询进行迭代 result-set object：-

$sql=mysql_query("SELECT friendName,createdDate FROM friends where userId='$userId'");
$json = array(); // create empty array
$i = 0; // start a counter
while($result=mysql_fetch_assoc($sql)){ // start iteration on result-set object
    // fetch values one-by-one and assing to them in the array
    $json[$i]['friendName'] = $result['friendName'];
    $json[$i]['createdDate'] = $result['createdDate'];
    $i++; // increase the counter so that values will assign to the new indexes every-time (prevent from over-writing)
}
if(count($json)>0){ // check array have some values or not
 // now you have all records in $json array and here you can do your next code whatever you want based on this resultant array
}else{
$json = array( "msg" => "No infomations Found");
}
header('Content-type: application/json'); //i don't know what purpose this line will serve, so check your self.

如何从 MySQL table 中获取 php 网络服务中的所有记录

how to get all the records from MySQL table in php web services

php

mysql